Construct a triangle ZXC, where
Now, constructing a
Steps for construction:
(a) Make a line segment ZX = 5.8 cm.
(b) At Z, make an angle
(c) At X, draw
(d) ZP and XQ intersect at the point C.
Thus we have the required triangle ZXC:
Construct a triangle ABC if AB = 5 cm,
We know ,sum of the angles of a triangle = 180 .°
105. 40 °+ 40°+
Constructing a triangle ABC whose
Steps of construction:
(a) Make a line segment PQ = 5 cm.
(b) At A, make an angle
(c) At B, make an angle
(d) QA and BP intersect at point C.
Thus, we have the required triangle ABC.
Can you construct a
We know the angles of a triangle sum up to 180o
Thus, we have
Since the sum of the angles is coming more than 180o, this triangle construction is not possible.