# NCERT Solutions for Class 7 Maths Exercise 10.2 Chapter 10 Practical Geometry

NCERT Solutions for Class 7 Maths Exercise 10.2 Chapter 10 Practical Geometry in simple PDF are given here. This exercise of NCERT Maths Solutions for Class 7 Chapter 10 contains topics related to constructing a triangle when the lengths of its three sides are known (SSS Criterion). By practising these NCERT Solutions for Class 7 Maths, Chapter 10 Practical Geometry, students can score high marks in the exam.

## Download the PDF of NCERT Solutions For Class 7 Maths Chapter 10 Practical Geometry â€“ Exercise 10.2

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### Access Other Exercises of NCERT Solutions For Class 7 Maths Chapter 10 â€“ Practical Geometry

Exercise 10.1 Solutions

Exercise 10.3 Solutions

Exercise 10.4 Solutions

Exercise 10.5 Solutions

### Access Answers to NCERT Class 7 Maths Chapter 10 â€“ Practical Geometry Exercise 10.2

1. Construct Î”XYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm

Solution:-

Steps of construction:

1. Draw a line segment YZ = 5 cm.

2. With Z as a center and radius 6 cm, draw an arc.

3. With Y as a center and radius 4.5 cm, draw another arc, cutting the previous arc at X.

4. Join XY and XZ.

Then, Î”XYZ is the required triangle.

2. Construct an equilateral triangle of side 5.5 cm.

Solution:-

Steps of construction:

1. Draw a line segment AB = 5.5 cm.

2. With A as a center and radius 5.5 cm, draw an arc.

3. With B as a center and radius 5.5 cm, draw another arc, cutting the previous arc at C.

4. Join CA and CB.

Then, Î”ABC is the required equilateral triangle.

3. Draw Î”PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?

Solution:-

Steps of construction:

1. Draw a line segment QR = 3.5 cm.

2. With Q as a center and radius 4 cm, draw an arc.

3. With R as a center and radius 4 cm, draw another arc, cutting the previous arc at P.

4. Join PQ and PR.

Then, Î”PQR is the required isosceles triangle.

4. Construct Î”ABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure âˆ B.

Solution:-

1. Draw a line segment BC = 6 cm.

2. With B as a center and radius 2.5 cm, draw an arc.

3. With C as a center and radius 6.5 cm, draw another arc, cutting the previous arc at A.

4. Join AB and AC.

Then, Î”ABC is the required triangle.

5. When we measure the angle B of triangle by protractor, then angle is equal to âˆ B = 90o

#### 1 Comment

1. prikshitverma

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