NCERT Solutions for Class 8 Maths Chapter 2 - Linear Equations in One Variable Exercise 2.6

The NCERT exercise questions of Chapter 2 help the students in preparing for their exam more efficiently. NCERT Solutions at BYJU’S are prepared according to the methods prescribed in the latest CBSE syllabus. Our subject experts have prepared the NCERT Solutions for Class 8 Maths with utmost care, and explain each and every step in detail. Download free mathematics NCERT Solutions and practise the concepts.

NCERT Solutions for Class 8 Maths Chapter 2 – Linear Equations in One Variable Exercise 2.6

Download PDF Download PDF

 

Access Other Exercise Solutions of Class 8 Maths Chapter 2 – Linear Equations in One Variable

Exercise 2.1 Solutions 12 Questions (12 Short Answer Questions)
Exercise 2.2 Solutions 16 Questions (6 Long Answer Questions, 10 Short Answer Questions)
Exercise 2.3 Solutions 10 Questions (3 Long Answer Questions, 7 Short Answer Questions)
Exercise 2.4 Solutions 10 Questions (4 Long Answer Questions, 6 Short Answer Questions)
Exercise 2.5 Solutions 10 Questions (1 Long Answer Questions, 9 Short Answer Questions)

Access Answers of Maths NCERT Class 8 Chapter 2 – Linear Equations in One Variable Exercise 2.6 Page Number 35

Solve the following equations.

1. (8x – 3)/3x = 2

Solution:

(8x – 3)/3x = 2

⇒ 8x/3x – 3/3x = 2

⇒ 8/3 – 1/x = 2

⇒ 8/3 – 2 = 1/x

⇒ (8 – 6)/3 = 1/x

⇒ 2/3 = 1/x

⇒ x = 3/2

2. 9x/(7 – 6x) = 15

Solution:

9x/(7 – 6x) = 15

⇒ 9x = 15(7 – 6x)

⇒ 9x = 105 – 90x

⇒ 9x + 90x = 105

⇒ 99x = 105

⇒ x = 105/99 = 35/33

3. z/(z + 15) = 4/9

Solution:

z/(z + 15) = 4/9

⇒ z = 4/9 (z + 15)

⇒ 9z = 4(z + 15)

⇒ 9z = 4z + 60

⇒ 9z – 4z = 60

⇒ 5z = 60

⇒ z = 12

4. (3y + 4)/(2 – 6y) = -2/5

Solution:

(3y + 4)/(2 – 6y) = -2/5

⇒ 3y + 4 = -2/5 (2 – 6y)

⇒ 5(3y + 4) = -2(2 – 6y)

⇒ 15y + 20 = -4 + 12y

⇒ 15y – 12y = -4 – 20

⇒ 3y = -24

⇒ y = -8

5. (7y + 4)/(y + 2) = -4/3

Solution:

(7y + 4)/(y + 2) = -4/3

⇒ 7y + 4 = -4/3 (y + 2)

⇒ 3(7y + 4) = -4(y + 2)

⇒ 21y + 12 = -4y – 8

⇒ 21y + 4y = -8 – 12

⇒ 25y = -20

⇒ y = -20/25 = -4/5

6. The ages of Hari and Harry are in the ratio 5:7. Four years from now the ratio of their ages will be 3:4. Find their present ages.

Solution:

Let the age of Hari be 5x and Harry be 7x. 4 years later,

Age of Hari = 5x + 4 Age of Harry = 7x + 4

According to the question,

(5x + 4)/(7x + 4) = ¾

⇒ 4(5x + 4) = 3(7x + 4)

⇒ 20x + 16 = 21x + 12

⇒ 21x – 20x = 16 – 12

⇒ x = 4

Hari age = 5x = 5 × 4 = 20 years

Harry age = 7x = 7 × 4 = 28 years

7. The denominator of a rational number is greater than its numerator by 8. If the numerator is increased by 17 and the denominator is decreased by 1, the number obtained is 3/2. Find the rational number.

Solution:

Let the numerator be x then denominator will be (x + 8)

According to the question,

(x + 17)/(x + 8 – 1) = 3/2

⇒ (x + 17)/(x + 7) = 3/2

⇒ 2(x + 17) = 3(x + 7)

⇒ 2x + 34 = 3x + 21

⇒ 34 – 21 = 3x – 2x

⇒ 13 = x

The rational number is x/(x + 8) = 13/21


Exercise 2.6 of NCERT Solutions for Class 8 Maths Chapter 2 – Linear Equations in One Variable is based on the topic “Equations Reducible to the Linear Form”. By solving the questions in Exercise 2.6, students will be able to understand the type of equations that can be reduced to linear form. This reduction is done to help the students in solving the problems easily.

Also, explore –

NCERT Solutions for Class 8 Maths

NCERT Solutions for Class 8 

Comments

Leave a Comment Cancel reply

Your Mobile number and Email id will not be published.

*

*

  1. This site is so helpful 😃 👍🏻😊♥️

close
close

Play

&

Win