 # NCERT Solutions for Class 8 Maths Chapter 5- Data Handling Exercise 5.3

Chapter 5, Data Handling, Exercise 5.3 begins from page number 87 of the NCERT textbook for Class 8. The exercise covers the portions in which topics related to probability and chances of an event are present. In other words, we can say that the NCERT Solutions of this exercise contains the answers to all the questions present in exercise 5.3, that are purely based on the probable outcomes of an event and more, which is of high significance in real life.

The subject experts at BYJU’S make sure that the questions present in the NCERT textbooks are solved in the easiest way possible. The NCERT Solutions for Class 8 Maths can help the students in their examination preparation, as well as in checking if the answers they gave to the questions are correct.

### Download PDF of NCERT Solutions for Class 8 Maths Chapter 5- Data Handling Exercise 5.3   ### Access Other Exercise Solutions of Class 8 Maths Chapter 5- Data Handling

Exercise 5.1 Solutions 5 Questions (5 Short Answer Questions)

Exercise 5.2 Solutions 5 Questions (3 Long Answer Questions and 2 Short Answer Questions)

### Access Answers to NCERT Class 8 Maths Chapter 5- Data Handling Exercise 5.3 Page Number 87

1. List the outcomes you can see in these experiments.

(a) Spinning a wheel (b) Tossing two coins together Solution:

(a) There are four letters A, B, C and D in a spinning wheel. So there are 4 outcomes.

(b) When two coins are tossed together. There are four possible outcomes HH, HT, TH, TT.

2. When a die is thrown, list the outcomes of an event of getting

(i) (a) a prime number (b) not a prime number.

(ii) (a) a number greater than 5 (b) a number not greater than 5.

Solution:

(i) (a) Outcomes of event of getting a prime number are 2, 3 and 5.

(b) Outcomes of event of not getting a prime number are 1, 4 and 6.

(ii) (a) Outcomes of event of getting a number greater than 5 is 6.

(b) Outcomes of event of not getting a number greater than 5 are 1, 2, 3, 4 and 5.

3. Find the.

(a) Probability of the pointer stopping on D in (Question 1-(a))?

(b) Probability of getting an ace from a well shuffled deck of 52 playing cards?

(c) Probability of getting a red apple. (See figure below) Solution:

(a) In a spinning wheel, there are five pointers A, A, B, C, D. So there are five

outcomes. Pointer stops at D which is one outcome.

So the probability of the pointer stopping on D = 1/5

(b) There are 4 aces in a deck of 52 playing cards. So there are four events of getting an ace.

So, probability of getting an ace = 4/52 = 1/13

(c) Total number of apples = 7

Number of red apples = 4

Probability of getting red apple = 4/7

4. Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of .

(i) getting a number 6?

(ii) getting a number less than 6? (iii) getting a number greater than 6? (iv)getting a 1-digit number?

Solution:

(i) Outcome of getting a number 6 from ten separate slips is one.

∴, probability of getting a number 6 = 1/10

(ii) Numbers less than 6 are 1, 2, 3, 4 and 5 which are five. So there are 5 outcomes.

∴, probability of getting a number less 6 =5/10 = ½

(iii)Number greater than 6 out of ten that are 7, 8, 9, 10. So there are 4 possible outcomes.

∴, probability of getting a number greater than 6 = 4/10 = 2/5

(iv) One digit numbers are 1, 2, 3, 4, 5, 6, 7, 8, 9 out of ten.

∴, probability of getting a 1-digit number = 9/10

5. If you have a spinning wheel with 3 green sectors, 1 blue sector and 1 red sector, what is the probability of getting a green sector? What is the probability of getting a non-blue sector?

Solution:

A total of five sectors are present.

Out of the five sectors, three sectors are green.

∴, probability of getting a green sector = 3/5

Out of the five sectors, one sector is blue. Hence, Non-blue sectors = 5 – 1 = 4 sectors

∴, probability of getting a non-blue sector= 4/5

6. Find the probabilities of the events given in Question 2.

Solution:

When a die is thrown, there are total six outcomes, i.e., 1, 2, 3, 4, 5 and 6.

(i)

(a) 2, 3, 5 are the prime numbers. So there are 3 outcomes out of 6.

∴,probability of getting a prime number =3/6 = ½

(b) 1, 4, 6 are not the prime numbers. So there are 3 outcomes out of 6.

∴,probability of getting a prime number =3/6 = ½

(ii)

(c) Only 6 is greater than 5.

So there is one outcome out of 6.

∴,probability of getting a number greater than 5= 1/6

(d) Numbers not greater than 5 are 1, 2, 3, 4 and 5. So there are 5 outcomes out of 6.

∴,probability of not getting a number greater than 5= 5/6

The Class 8 Maths Chapter 5, Data Handling covers a wide range of topics with the three exercises present in the chapter. Exercise 5.3 can be considered to be the basic step towards the wide concept of probability, that would be taught in higher classes. 6 Questions are present in this exercise, out of which, 4 questions are short answer type questions and 2 questions are long answer type questions. The students study the following topics under Chance and Probability prior to solving Exercise 5.3.

• Getting a result
• Equally, likely outcomes