**NCERT Solutions for Class 8 Maths Chapter 5 Data Handling** is crucial for the students of the 8th standard to clear their doubts and excel in their examinations. These solutions help students to gain a better understanding of the topic. BYJUâ€™S provides NCERT Solutions to help the students not only to sort out their difficulties in solving problems but also to develop a deeper understanding of the related concepts and to ease the fear of Maths.

### Download Exclusively Curated Chapter Notes for Class 8 Maths Chapter â€“ 5 Data Handling

### Download Most Important Questions for Class 8 Maths Chapter â€“ 5 Data Handling

Students can also download the PDF of NCERT Class 8 Maths Solutions for Data Handling Chapter 5 or can view it online by following the links. Data Handling is an important concept that assures the uprightness of the research data. We have information in the form of a numerical figure, no matter which field we take. Every value of this kind is known as an observation. Usually, the set of all the observations is called data. Different data management methods are used to handle, termed as data, which will be discussed in this chapter as well as in the higher classes. These solutions for Data handling are designed by subject experts, as per the CBSE syllabus for the year 2023-24, prescribed by the board itself.

## NCERT Solutions for Class 8 Maths 5 â€“ Data Handling

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### Access answers to NCERT Class 8 Maths Chapter 5 â€“ Data Handling

## Exercise 5.1 Page: 76

**1. For which of these would you use a histogram to show the data?**

** (a) The number of letters for different areas in a postmanâ€™s bag.**

**(b) The height of competitors in an athletics meet.**

**(c) The number of cassettes produced by 5 companies.**

**(d) The number of passengers boarding trains from 7.00 a.m. to 7.00 p.m. at a station. Give a reason for each.**

Solution:

We know that a Histogram is a graphical representation of data if the data is represented using class interval.

Since the cases mentioned in options (b) and (d) can be divided into class intervals, the histogram can be used to show the data.

Similarly, since the cases mentioned in options (a) and (c) cannot be divided into class intervals, histograms cannot be used to represent the data.

**2. The shoppers who come to a departmental store are marked as man (M), woman (W), boy (B) or girl (G). The following list gives the shoppers who came during the first hour of the morning.**

W W W G B W W M G G M M W W W W G B M W B G G M W W M M W W W M W B W G M W W W W G W M M W M W G W M G W M M B G G W.

Make a frequency distribution table using tally marks. Draw a bar graph to illustrate it.

Solution:

Frequency distribution table:

Bar-graph:

**3. The weekly wages (in â‚¹) of 30 workers in a factory are:**

830, 835, 890, 810, 835, 836, 869, 845, 898, 890, 820, 860, 832, 833, 855, 845, 804, 808,

812, 840, 885, 835, 835, 836, 878, 840, 868, 890, 806, 840.

Using tally marks, make a frequency table with intervals as 800 â€“ 810, 810 â€“ 820 and so on.

Solution:

The frequency table with intervals as 800 â€“ 810, 810 â€“ 820 and so on, using tally marks, is given below:

**4. Draw a histogram for the frequency table made for the data in Question 3 and answer the following questions.**

**(i) Which group has the maximum number of workers?**

**(ii) How many workers earn â‚¹ 850 and more?**

**(iii) How many workers earn less than â‚¹ 850? **

Solution:

(i) 830-840 is the group having a maximum number of workers, 9, compared to other groups.

(ii) Workers earning â‚¹ 850 and more= 1+3+1+1+4=10

(iii) Workers earning less than â‚¹ 850= 3+2+1+9+5=20

**5. The number of hours for which students of a particular class watched television during holidays is shown in the given graph.**

Answer the following:

**(i) For how many hours did the maximum number of students watch TV?**

**(ii) How many students watched TV for less than 4 hours?**

**(iii) How many students spent more than 5 hours watching TV?**

Solution:

(i) 32 students watched TV for 4-5 hours. âˆ´ The maximum number of students who watched TV for 4 â€“ 5 hours.

(ii) The number of students who watched TV less than 4 hours= 22+8+4=34

(iii) The number of students who spent more than 5 hours watching TV

=8+6=14

## Exercise 5.2 Page: 82

**1. A survey was made to find the type of music that a certain group of young people liked in a city.**

An adjoining pie chart shows the findings of this survey. From this pie chart, answer the following:

**(i) If 20 people liked classical music, how many young people were surveyed?**

**(ii) Which type of music is liked by the maximum number of people?**

**(iii) If a cassette company were to make 1000 CDs, how many of each type would they**

make?

Solution:

(i) 10% represents 100 people.

âŸ¹20% represents = (100Ã—20)/10 = 200

âˆ´ 200 people were surveyed.

(ii) Since 40% of the total people surveyed liked light music and no other form of song was liked more than that, we can conclude that light music is liked by the maximum number of people.

(iii) CDs of classical music = (10 Ã— 1000)/100 = 100

CDs of semi-classical music = (20 Ã— 1000)/100 = 200

CDs of light music = (40 Ã— 1000)/100 = 400

CDs of folk music = (30 Ã— 1000)/100 = 300

**2. A group of 360 people were asked to vote for their favourite season from the three:**

seasons rainy, winter and summer.

**(i) Which season got the most votes?**

**(ii)Find the central angle of each sector.**

**(iii) Draw a pie chart to show this information**

Solution:

(i) According to the table given in the question, the winter season got the most votes.

(ii) Central angle of summer season= (90Ã—360)/360= 90o

Central angle of rainy season= (120Ã—360)/360= 120o

Central angle of winter season= (150Ã—360)/360= 150o

(iii)

**3. Draw a pie chart showing the following information. The table shows the colours preferred by a group of people.**

Solution:

Here, central angle = 360o Total number of people = 36

**4. The adjoining pie chart gives the marks scored in an examination by a student in Hindi, English, Mathematics, Social Science and Science. If the total marks obtained by the students were 540, answer the following questions.**

**(i) In which subject did the student score 105 marks?**

(Hint: for 540 marks, the central angle = 360Â°. So, for 105 marks, what is the central angle?)

**(ii) How many more marks were obtained by the student in Mathematics than in Hindi?**

**(iii) Examine whether the sum of the marks obtained in Social Science and Mathematics is more than that in Science and Hindi (Hint: Just study the central angles).**

Solution:

(i) The student scored 105 marks in Hindi.

(ii) Marks obtained in Mathematics = 135 Marks obtained in Hindi = 105 Difference = 135 â€“ 105 = 30

Thus, 30 more marks were obtained by the student in Mathematics than in Hindi.

(iii) The sum of marks in Social Science and Mathematics = 97.5 + 135 = 232.5 The sum of marks in Science and Hindi = 120 + 105 = 225

âˆ´ the sum of the marks in Social Science and Mathematics is more than in Science and Hindi.

**5. The number of students in a hostel speaking different languages is given below. Display the data in a pie chart.**

Solution:

NCERT Solution for Class 8 Maths Chapter 5 â€“ Data Handling

## Exercise 5.3 Page: 87

**1. List the outcomes you can see in these experiments.**

**(a) Spinning a wheel (b) Tossing two coins together**

Solution:

(a) There are four letters A, B, C and D in a spinning wheel. So, there are 4 outcomes.

(b) When two coins are tossed together. There are four possible outcomes HH, HT, TH, and TT.

**2. When a die is thrown, list the outcomes of an event of getting**

**(i) (a) a prime number (b) not a prime number**

**(ii) (a) a number greater than 5 (b) a number not greater than 5**

Solution:

(i) (a) Outcomes of the event of getting a prime number are 2, 3 and 5.

(b) Outcomes of the event of not getting a prime number are 1, 4 and 6.

(ii) (a) Outcomes of the event of getting a number greater than 5 is 6.

(b) Outcomes of the event of not getting a number greater than 5 are 1, 2, 3, 4 and 5.

**3. Find the.**

**(a) Probability of the pointer stopping on D in (Question 1-(a)).**

**(b) Probability of getting an ace from a well-shuffled deck of 52 playing cards.**

**(c) Probability of getting a red apple. (See figure below)**

Solution:

(a) In a spinning wheel, there are five pointers A, A, B, C, D. So, there are five

outcomes. The pointer stops at D, which is one outcome.

So, the probability of the pointer stopping on D = 1/5

(b) There are 4 aces in a deck of 52 playing cards. So, there are four events for getting an ace.

So, the probability of getting an ace = 4/52 = 1/13

(c) Total number of apples = 7

Number of red apples = 4

Probability of getting a red apple = 4/7

**4. Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of**

**(i) getting a number 6?**

**(ii) getting a number less than 6? (iii) getting a number greater than 6? (iv)getting a 1-digit number?**

Solution:

(i) Outcome of getting a number 6 from ten separate slips is one.

âˆ´ probability of getting a number 6 = 1/10

(ii) Numbers less than 6 are 1, 2, 3, 4 and 5, which are five. So, there are 5 outcomes.

âˆ´ probability of getting a number less 6 =5/10 = Â½

(iii) Number greater than 6 out of ten that are 7, 8, 9, 10. So there are 4 possible outcomes.

âˆ´ probability of getting a number greater than 6 = 4/10 = 2/5

(iv) One-digit numbers are 1, 2, 3, 4, 5, 6, 7, 8, 9 out of ten.

âˆ´ probability of getting a 1-digit number = 9/10

**5. If you have a spinning wheel with 3 green sectors, 1 blue sector and 1 red sector, what is the probability of getting a green sector? What is the probability of getting a non-blue sector?**

Solution:

A total of five sectors are present.

Out of the five sectors, three sectors are green.

âˆ´ probability of getting a green sector = 3/5

Out of the five sectors, one sector is blue. Hence, non-blue sectors = 5 â€“ 1 = 4 sectors

âˆ´ probability of getting a non-blue sector= 4/5

**6. Find the probabilities of the events given in Question 2.**

Solution:

When a die is thrown, there is a total of six outcomes, i.e., 1, 2, 3, 4, 5 and 6.

(i)

(a) 2, 3, 5 are the prime numbers. So, there are 3 outcomes out of 6.

âˆ´ probability of getting a prime number =3/6 = Â½

(b) 1, 4, 6 are not the prime numbers. So, there are 3 outcomes out of 6.

âˆ´ probability of getting a prime number =3/6 = Â½

(ii)

(c) Only 6 is greater than 5.

So there is one outcome out of 6.

âˆ´ probability of getting a number greater than 5= 1/6

(d) Numbers not greater than 5 are 1, 2, 3, 4 and 5. So there are 5 outcomes out of 6.

âˆ´ probability of not getting a number greater than 5= 5/6

Also AccessÂ |

NCERT Exemplar for Class 8 Maths Chapter 5 |

CBSE Notes for Class 8 Maths Chapter 5 |

## NCERT Solutions for Class 8 Maths Chapter 5 â€“ Data Handling

Solving the NCERT Solutions for Class 8 is very important from the CBSE board examination point of view. Data Handling is one of the chapters in Class 8 Maths that contains the concepts that are likely to be used in daily life. The chapter deals with different concepts related to Data Handling. Let us have a look at some of them.

- Data mostly available to us in an unorganised form is called raw data.
- In order to draw meaningful inferences from any data, we need to organise the data systematically.
- Frequency gives the number of times that a particular entry occurs.
- Raw data can be â€˜groupedâ€™ and presented systematically through â€˜grouped frequency distributionâ€™.
- Grouped data can be presented using a histogram. The histogram is a type of bar diagram, where the class intervals are shown on the horizontal axis and the heights of the bars show the frequency of the class interval. Also, there is no gap between the bars as there is no gap between the class intervals.
- Data can also be presented using a circle graph or pie chart. A circle graph shows the relationship between a whole and its parts.
- There are certain experiments whose outcomes have an equal chance of occurring.
- A random experiment is one whose outcome cannot be predicted exactly in advance.
- Outcomes of an experiment are equally likely if each has the same chance of occurring. Probability of an event = Number of outcomes that make an event/Total number of outcomes of the experiment, when the outcomes are equally likely.
- One or more outcomes of an experiment make an event.
- Chances and probability are related to real life.

The main topics covered in this chapter include:

5.1 Looking for Information

5.2 Organising Data

5.3 Grouping Data

5.3.1 Bars with a difference

5.4 Circle Graph or Pie Chart

5.4.1 Drawing pie charts

5.5 Chance and Probability

5.5.1 Getting a Result

5.5.2 Equally Likely Outcomes

5.5.3 Linking Chances to Probability

5.5.4 Outcomes as Events

5.5.5 Chances and Probability Related to Real Life

Exercise 5.1 Solutions 5 Questions (5 Short Answer Questions)

Exercise 5.2 Solutions 5 Questions (3 Long Answer Questions and 2 Short Answer Questions)

Exercise 5.3 Solutions 6 Questions (2 Long Answer Questions and 4 Short Answer Questions)

## NCERT Solutions for Class 8 Maths Chapter 5 â€“ Data Handling

Information that we collect in our day-to-day life is called Data. The graphical representation of the data collected gives a clear idea of what it represents. The different types of graphs used to represent the data include pictographs, bar graphs, double bar graphs, pie charts, etc. Chapter 5 of Class 8 Maths Data Handling deals with organising data and grouping the data. The data can be grouped using the frequency distribution table. In this chapter, the students also learn about the chances or probability of an event as well as how these probabilities can be represented.

Studying Chapter 5 of Class 8 Data Handling helps the students in

- Reading bar-graphs, ungrouped data, arranging it into groups, representation of grouped data through bar graphs, constructing and interpreting bar graphs.
- Simple pie charts with reasonable data numbers.
- Consolidating and generalising the notion of chance in events like tossing coins, dice etc. Relating it to chance in life events.
- Visual representation of frequency outcomes of repeated throws of the same kind of coins or dice.
- Throwing a large number of identical dice/coins together and aggregating the result of the throws to get a large number of individual events.
- Observing the aggregating numbers over a large number of repeated events.
- Comparing with the data for a coin.
- Observing strings of throws, the notion of randomness.

**Disclaimer:**

**Dropped topics â€“** 5.2 Organising Data, 5.3 Grouping Data and 5.3.1 Bars with a difference.

## Frequently Asked Questions on NCERT Solutions for Class 8 Maths Chapter 5

### Where can I get the accurate solution for NCERT Solution for Class 8 Maths Chapter 5?

### Is it necessary to solve each problem provided in the NCERT Solution for Class 8 Maths Chapter 5?

### List out the concepts covered in NCERT Solution for Class 8 Maths Chapter 5.

5.1 Looking for Information

5.2 Organising Data

5.3 Grouping Data

5.3.1 Bars with a Difference

5.4 Circle Graph or Pie Chart

5.4.1 Drawing Pie Charts

5.5 Chance and Probability

5.5.1 Getting a Result

5.5.2 Equally Likely Outcomes

5.5.3 Linking Chances to Probability

5.5.4 Outcomes as Events

5.5.5 Chances and Probability Related to Real Life

By learning these concepts, students will be able to solve questions on Data handling.

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