NCERT Solutions for Class 8 Maths Chapter 11 Mensuration

NCERT Solutions for Class 8 Maths Chapter 11 Mensuration is a very important resource for CBSE students. It helps them get a fair idea on the chapter, specifically, the sort of questions that are possibly asked in the exam and the method of answering them. BYJU’S provides all exercise-wise NCERT Class 8 Maths Solutions to help students prepare for exam and clear doubts.

The branch of Mathematics that deals with geometric figures and their parameters like length, volume, shape, surface area, lateral surface area, etc are known as Mensuration. Here, the questions related to the concepts of mensuration are explained, covering all the important mensuration formulas and properties of different geometric shapes and figures. The problems related to perimeter and area of other plane closed figures like quadrilaterals are solved by subject experts at BYJU’S.

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NCERT Solutions CBSE Class 8 Maths Chapter 11 Mensuration Part 1
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NCERT Solutions for Class 8 Maths Chapter 11 Mensuration

In previous grade, students learnt about area and perimeter of closed plane figures such as circle, square, triangles, rectangles etc. In Class 8 CBSE Maths Chapter 11, students will learn about surface area and volume of solids such as cube, cuboid and cylinder, area of trapezium, area of quadrilateral, area of special quadrilaterals, area of a polygon, solid shapes, volume and capacity. Try NCERT Solutions for Class 8 Maths Chapter 11 problems with answers to top the concept because Mensuration is a topic widely used in real-life applications.

The topics discussed in the chapter revolves around:

1. Area of
(i) a trapezium = half of the sum of the lengths of parallel sides × perpendicular distance between
them.
(ii) a rhombus = half the product of its diagonals.
2. Surface area of a solid is the sum of the areas of its faces.
3. Surface area of
a cuboid = 2(lb + bh + hl)
a cube = 6l2
a cylinder = 2πr(r + h)
4. Amount of region occupied by a solid is called its volume.
5. Volume of
a cuboid = l × b × h
a cube = l3
a cylinder = πr2h
6. (i) 1 cm3= 1 mL
(ii) 1L = 1000 cm3
(iii) 1 m= 1000000 cm= 1000L

NCERT Solutions For Class 8 Maths Chapter 11 Exercises:

Get detailed solution for all the questions listed under below exercises:

Exercise 11.1 Solutions : 5 Questions (Long answers)

Exercise 11.2 Solutions : 11 Questions (Long answers)

Exercise 11.3 Solutions : 10 Questions (2 Short answers, 8 Long answers)

Exercise 11.4 Solutions : 8 Questions (2 Short answers, 6 Long answers)

Try these NCERT Solutions for Class 8 Maths Chapter 11 about surface area and volume of solids such as cube, cuboid and cylinder, and relationship between various geometrical solids. Students will also learn about different mathematical formulas while dealing with mensuration problems.

The main topics covered in this chapter include:

Exercise Topic
11.1 Introduction
11.2 Let us Recall
11.3 Area of Trapezium
11.4 Area of a General Quadrilateral
11.5 Area of a Polygon
11.6 Solid Shapes
11.7 Surface Area of Cube, Cuboid and Cylinder
11.8 Volume of Cube, Cuboid and Cylinder
11.9 Volume and Capacity

 

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