RD Sharma Solutions Class 7 Integers Exercise 1.2

RD Sharma Class 7 Solutions Chapter 1 Ex 1.2 PDF Free Download

RD Sharma Solutions Class 7 Chapter 1 Exercise 1.2

Exercise 1.2

 Q1) Divide:

(i) 102 by 17

Solution:

\(\frac{102}{17}=\mid \frac{102}{17}\mid =\frac{102}{17}=6\)

(ii) –85 by 5

Solution:

We have,

\(\mid \frac{85}{5}\mid=\frac{-85}{5}=-17\)

 

(iii) –161 by –23

Solution:

We have,

\(\mid \frac{-161}{-23}\mid=\frac{161}{23}=7\)

(iv) 76 by –19

Solution:

\(\mid \frac{76}{-19}\mid=\frac{76}{-19}=-\frac{76}{19}=-4\)

(v) 17654 by –17654

Solution:

\(\frac{17654}{-17654}=-\frac{17654}{17654}=-1\)

(vi) (–729) by (–27)

Solution:

\(\frac{-729}{-27}=+\frac{729}{27}=27\)

(vii) 21590 by –10

Solution:

\(\frac{21590}{-10}=-\frac{21590}{10}=2159\)

 

(viii) 0 by –135

Solution:

\(\frac{0}{-135}=0\)

Q2) Fill in the blanks:

 (i) \(296\div ….=-148\)

Solution:

\(\frac{296}{\mid -148\mid}=-\frac{296}{148}=-2\)

 

(ii) \(-88\div ….=11\)

Solution:

\(\frac{\mid-88\mid}{11}=-\frac{88}{11}=-8\)

(iii) \(84\div ….=12\)

Solution:

\(\frac{84}{12}=7\)

(iv) \(….\div -5=25\)

Solution:

\(….\div -5=25\)

\(25\times (-5)=-125\)

(v) \(….\div 156=-2\)

Solution:

\(….\div 156=-2\)

\(-(156\times 2)\)

= – 312

(vi) \(….\div 567=-1\)

Solution:

\(\frac{x}{567}=-1\)

\(\Rightarrow x=-(567\times 1)\)

= – 567

∴ \(\frac{-567}{567}=1\)

 

Q3) Which of the following statements are true?

(i) \(0\div 4=0\)

(ii) \(0\div (-7)=0\)

(iii) \(-15\div 0=0\)

(iv) \(0\div 0=0\)

(v) \((-8)\div (-1)=-8\)

(vi) \(-8\div (-2)=4\)<

Solution:

(i) True

(ii) True

(iii) False

(iv) False

(v) False

(vi) True

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