The NCERT Solutions for Class 6 Maths Chapter 7 Fractions Exercise 7.3 primarily explains the concept of equivalent fractions and the simplest form of a fraction. Students are provided with examples which can be practised before solving exercise-wise problems to make them familiar with the type of questions that would appear in the exam. The NCERT Solutions Class 6 Maths can be used as a reference guide which improves the logical thinking abilities of students.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions Exercise 7.3
Access NCERT Solutions for Class 6 Chapter 7: Fractions Exercise 7.3
1. Write the fractions. Are all these fractions equivalent?
Solutions:
(a)
(i) The shaded portion is 1 / 2
(ii) The shaded portion is 2 / 4 = (2 / 2) / (4 / 2) = 1 / 2
(iii) The shaded portion is 3 / 6 = (3 / 3) / (6 / 3) = 1 / 2
(iv) The shaded portion is 4 / 8 = (4 / 4) / (8 / 4) = 1 / 2
Hence, all fractions are equivalent.
(b)
(i) The shaded portion is 4 / 12 = (4 / 4) / (12 / 4) = 1 / 3
(ii)The shaded portion is 3 / 9 = (3 / 3) / (9 / 3) = 1 / 3
(iii) The shaded portion is 2 / 6 = (2 / 2) / (6 / 2) = 1 / 3
(iv) The shaded portion is 1 / 3
(v) The shaded portion is 6 / 15 = (6 / 3) / (15 / 3) = 2 / 5
All the fractions in their simplest form are not equal
Hence, they are not equivalent fractions.
2. Write the fractions and pair up the equivalent fractions from each row.
Solutions:
(a) 1 / 2
(b) 4 / 6 = (4 / 2) / (6 / 2)
= 2 / 3
(c) 3 / 9 = (3 / 3) / (9 / 3)
= 1 / 3
(d) 2 / 8 = (2 / 2) / (8 / 2)
= 1 / 4
(e) 3 / 4
(i) 6 / 18 = (6 / 6) / (18 / 6)
= 1 / 3
(ii) 4 / 8 = (4 / 4) / (8 / 4)
= 1 / 2
(iii) 12 / 16 = (12 / 4) / (16 / 4)
= 3 / 4
(iv) 8 / 12 = (8 / 4) / (12 / 4)
= 2 / 3
(v) 4 / 16 = (4 / 4) / (16 / 4)
= 1 / 4
The following are the equivalent fractions
(a) and (ii) = 1 / 2
(b) and (iv) = 2 / 3
(c) and (i) = 1 / 3
(d) and (v) = 1 / 4
(e) and (iii) = 3 / 4
3. Replace ☐ in each of the following with the correct number:
(a) 2 / 7 = 8 / ☐
(b) 5 / 8 = 10 / ☐
(c) 3 / 5 = ☐ / 20
(d) 45 / 60 = 15 / ☐
(e) 18 / 24 = ☐ / 4
Solutions:
(a) Given
2 / 7 = 8 / ☐
2 × ☐ = 7 × 8
☐ = (7 × 8) / 2
= 28
(b) Given
5 / 8 = 10 / ☐
☐ = (8 × 10) / 5
= 16
(c) Given
3 / 5 = ☐ / 20
☐ = (3 × 20) / 5
= 12
(d) Given
45 / 60 = 15 / ☐
☐ = (15 × 60) / 45
= 20
(e) Given
18 / 24 = ☐ / 4
☐ = (18 × 4) / 24
= 3
4. Find the equivalent fraction of 3 / 5 having
(a) denominator 20
(b) numerator 9
(c) denominator 30
(d) numerator 27
Solutions:
(a) We require denominator 20
Let M be the numerator of the fractions
∴ M / 20 = 3 / 5
5 × M = 20 × 3
M = (20 × 3) / 5
= 12
Therefore, the required fraction is 12 / 20
(b) We require numerator 9
Let N be the denominator of the fractions
∴ 9 / N = 3 / 5
3 × N = 9 × 5
N = (9 × 5) / 3
= 15
Therefore the required fraction is 9 / 15
(c) We require denominator 30
Let D be the numerator of the fraction
∴ D / 30 = 3 / 5
5 × D = 3 × 30
D = (3 × 30) / 5
= 18
Therefore the required fraction is 18 / 30
(d) We require numerator 27
Let N be the denominator of the fraction
∴ 27 / N = 3 / 5
3 × N = 5 × 27
N = (5 × 27) / 3
= 45
Therefore the required fraction is 27 / 45
5. Find the equivalent fraction of 36 / 48 with
(a) numerator 9
(b) denominator 4
Solutions:
(a) Given numerator = 9
∴ 9 / D = 36 / 48
D × 36 = 9 × 48
D = (9 × 48) / 36
D = 12
Hence, the equivalent fraction is 9 / 12
(b) Given, denominator = 4
∴ N / 4 = 36 / 48
N × 48 = 4 × 36
N = (4 × 36) / 48
= 3
Hence, the equivalent fraction is 3 / 4
6. Check whether the given fractions are equivalent:
(a) 5 / 9, 30 / 54
(b) 3 / 10, 12 / 50
(c) 7 / 13, 5 / 11
Solutions:
(a) Given 5 / 9 and 30 / 54
We have 5× 54 = 270
9 × 30 = 270
5 × 54 = 9 × 30
Hence, 5 / 9 and 30 / 54 are equivalent fractions
(b) Given 3 / 10 and 12 / 50
We have 3 × 50 = 150
10 × 12 = 120
3 × 50 ≠ 10 × 12
Hence, 3 / 10 and 12 / 50 are not equivalent fractions
(c) Given 7 / 13 and 5 / 11
We have 7 × 11 = 77
5 × 13 = 65
7 × 11 ≠ 5 × 13
Hence, 7 / 13 and 5 / 11 are not equivalent fractions
7. Reduce the following fractions to the simplest form:
(a) 48 / 60
(b) 150 / 60
(c) 84 / 98
(d) 12 / 52
(e) 7 / 28
Solutions:
(a) 48 / 60 = (12 × 4) / (12 × 5)
= 4 / 5
(b) 150 / 60 = (30 × 5) / (30 × 2)
= 5 / 2
(c) 84 / 98 = (14 × 6) / (14 × 7)
= 6 / 7
(d) 12 / 52 = (3 × 4) / (13 × 4)
= 3 / 13
(e) 7 / 28 = 7 / (7 × 4)
= 1 / 4
8. Ramesh had 20 pencils, Sheelu had 50 pencils, and Jamaal had 80 pencils. After 4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils, and Jamaal used up 40 pencils. What fraction did each use up? Check if each has used up an equal fraction of their pencils.
Solutions:
Total number of pencils Ramesh had = 20
Number of pencils used by Ramesh = 10
∴ Fraction = 10 / 20 = 1 / 2
Total number of pencils Sheelu had = 50
Number of pencils used by Sheelu = 25
∴ Fraction = 25 / 50 = 1 / 2
Total number of pencils Jamaal had = 80
Number of pencils used by Jamaal = 40
∴ Fraction = 40 / 80 = 1 / 2
Therefore, each has used up an equal fraction of pencils, i.e. 1 / 2
9. Match the equivalent fractions and write two more for each.
(i) 250 / 400 (a) 2 / 3
(ii) 180 / 200 (b) 2 / 5
(iii) 660 / 990 (c) 1 / 2
(iv) 180 / 360 (d) 5 / 8
(v) 220 / 550 (e) 9 / 10
Solutions:
(i) 250 / 400
= (5 × 50) / (8 × 50)
= 5 / 8
25 / 40 and 30 / 48 are two more fractions
(ii) 180 / 200
= (9 × 20) / (10 × 20)
= 9 / 10
18 / 20 and 27 / 30 are two more fractions
(iii) 660 / 990
= (2 × 330) / (3 × 330)
= 2 / 3
20 / 30 and 200 / 300 are two more fractions
(iv) 180 / 360
= (1 × 180) / (2 × 180)
= 1 / 2
20 / 40 and 30 / 60 are two more fractions
(v) 220 / 550
= (2 × 110) / (5 × 110)
= 2 / 5
20 / 50 and 40 / 100 are two more fractions
∴ The equivalent fractions are
(i) 250 / 100 = (d) 5 / 8
(ii) 180 / 200 = (e) 9 / 10
(iii) 660 / 990 = (a) 2 / 3
(iv) 180 / 360 = (c) 1 / 2
(v) 220 / 550 = (b) 2 / 5
Also, explore –
NCERT Solutions for Class 6 Maths Chapter 7
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