 # RD Sharma Solutions For Class 7 Maths Exercise 11.4 Chapter 11 Percentage

### RD Sharma Class 7 Solutions Chapter 11 Ex 11.4 PDF Free Download

The PDF of RD Sharma Solutions for Class 7 exercise 11.4 are available here. The solutions are prepared by BYJU’S experts in Maths. The solutions for exercise wise problems are prepared after vast research is conducted on each topic. The step-wise solutions prepared by subject experts help students to solve problems with competence. By practising RD Sharma Solutions for Class 7, students will be able to solve all questions present in them without any difficulties. This exercise contains finding a percentage of a given number. By practising previous exercises, students thorough about per cent but here they learn about the calculation of percentage.

## Download the PDF of RD Sharma Solutions For Class 7 Chapter 11 – Percentage Exercise 11.4  ### Access answers to Maths RD Sharma Solutions For Class 7 Chapter 11 – Percentage Exercise 11.4

1. Find each of the following:

(i) 7% of Rs 7150

(ii) 40% of 400kg

(iii) 20% of 15.125liters

(iv) 3 (1/3) % of 90km

(v) 2.5% of 600meters

Solution:

(i) Given 7% of Rs 7150

= (7/100) × 7150

= Rs 500.50

(ii) Given 40% of 400kg

= (40/100) × 400

= 160kg

(iii) Given 20% of 15.125liters

= (20/100) × 15.125

= 3.025liters

(iv) Given 3 (1/3) % of 90km

We know that 3 (1/3) = (10/3)

= (10/300) × 90

= 3km

2. Find the number whose 12 ½ % is 64.

Solution:

Let the required number be x

Then according to the question, 12 ½ % × x = 64

= 12.5 % × x = 64

= (12.5 × 100) × x = 64

x = (64/100)/ 12.5

x = 64 × 8 = 512

Therefore 512 is the number whose 12 ½ % is 64.

3. What is the number, 6 ¼ % of which is 2?

Solution:

Let the required number be x

Then according to the question, 6 ¼ % × x = 64

= 6.25 % × x = 2

= (6.25/100) × x = 2

x = (2 × 100)/ 6.25

x = 2 × 16 = 32

Therefore 32 is the number whose 12 ½ % is 64.

4. If 6 is 50% of a number, what is that number?

Solution:

Let the required number be x

Given that 50 % of x = 6

(50/100) × x = 6

x = (300 × 2)/ 50

x = 12

The required number is 12