The PDF of RD Sharma Solutions for Exercise 11.5 of Class 7 Maths Chapter 11 Percentage is provided here. The questions present have been solved by BYJU’S experts in Maths, and this will help students solve the problems without any difficulties. This exercise contains six questions with many sub-questions. Students can obtain worthy results in the annual exam by practising RD Sharma Solutions for Class 7. The exercise deals with comparing two quantities and finding what per cent of one quantity is of the other quantity.
RD Sharma Solutions for Class 7 Maths Chapter 11 – Percentage Exercise 11.5
Access answers to Maths RD Sharma Solutions for Class 7 Chapter 11 – Percentage Exercise 11.5
Exercise 11.5 Page No: 11.9
1. What percent of
(i) 24 is 6?
(ii) Rs 125 is Rs 10?
(iii) 4km is 160 meters?
(iv) Rs 8 is 25 paise?
(v) 2 days is 8 hours?
(vi) 1 liter is 175ml?
Solution:
(i) According to the question, required percentage = (6/24) × 100
= (100/4)
= 25%
(ii) According to the question, required percentage = (10/125) × 100
= (1000/125)
= 8%
(iii) According to the question, required percentage = (160/4) × 100
We know that 1km = 1000 meters
Therefore 4km = 4000 meters
= (160/4000) × 100
= 4%
(iv) According to the question, required percentage = (25/8) × 100
We know that 1Rs = 100 paise
Therefore 8Rs = 800 paise
= (25/800) × 100
= (25/8)
= 3.125%
(v) We know that 1 day = 24 hours
1 hour = (1/24) day
8 hours = (8/24) day = (1/3) day
According to the question, required percentage = [(1/3)/2] × 100
= 100/6
= 16 2/3 %
(vi) We know that 1liter = 1000ml
According to the question, required percentage = (175/1000) × 100
= 17500/1000
= 17.50 %
2. What percent is equivalent to (3/8)?
Solution:
Given (3/8)
= (3/8) × 100
= 37.5%
3. Find the following:
(i) 8 is 4% of which number?
(ii) 6 is 60% of which number?
(iii) 6 is 30% of which number?
(iv) 12 is 25% of which number?
Solution:
(i) Let x be the required number
Given that 4% of x = 8
(4/100) × x = 8
x = (800/4)
x = 200
(ii) Let the required number be x
Given that 60% of x = 6
(60/100) × x = 6
x = (60/6)
x = 10
(iii) Let the required number be x
Given that 30% of x = 6
(30/100) × x = 6
x = (6 × 100)/30
x = 20
(iv) Let the required number be x
Given that 25% of x = 12
(25/100) × x = 12
x = (12 × 100)/25
x = 48
4. Convert each of the following pairs into percentages and find out which is more?
(i) 25 marks out of 30, 35 marks out of 40
(ii) 100 runs scored off 110 balls, 50 runs scored off 55 balls
Solution:
(i) Given 25 marks out of 30
Consider 25 marks out of 30 = (25/30) × 100
= (250/3)
= 83.33%
Also given that 35 marks out of 40
Now consider 35 marks out of 40 = (35/40) × 100
= 87.5%
Clearly 87.5 > 83.33
After converting into percentage 35 marks out of 40 = 87.5% is more
(ii) Given 100 runs scored off 110 balls
Consider 100 runs scored off 110 balls = (100/110) × 100
= 90.91%
Also given that 50 runs scored off 55 balls
Consider 50 runs scored off 55 balls = (50/55) × 100
= 90.91%
Here, both are equal.
5. Find 20% more than Rs.200.
Solution:
Consider 20% of 200 = (20/100) × 200
= Rs 40
Therefore, 20% more than Rs 200 = 200 + 40
= Rs 240
6. Find 10% less than Rs.150
Solution:
Consider 10% of 150 = (10/100) × 150
= Rs 15
Therefore, 10% less than Rs 150 = 150 – 15
= Rs 135
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