Students can view and download the PDF of RD Sharma Solutions for Class 7 Chapter 11 Percentage Exercise 11.6, available here. Our subject experts formulate these exercises to help learners with their exam preparation to achieve good marks in Maths. The solutions are step-wise and detailed to make learning easy for them. This exercise has fifteen verbally-based questions based on the topic of percentages to solve real-life problems. It also deals with an increase or decrease in percentage. To know more about these topics, it is advised to solve RD Sharma Solutions for Class 7.
RD Sharma Solutions for Class 7 Maths Chapter 11 – Percentage Exercise 11.6
Access answers to Maths RD Sharma Solutions For Class 7 Chapter 11 – Percentage Exercise 11.6
Exercise 11.6 Page No: 11.13
1. Ashu had 24 pages to write. By the evening, he had completed 25% of his work. How many pages were left?
Solution:
Given total number of pages Ashu had to write = 24
Number of pages Ashu completed by the evening = 25% of 24
= (25/100) × 24
= 600/100
= 6
Therefore number of pages left for completion = 24 – 6 = 18 pages
2. A box contains 60 eggs. Out of which 16 2/3 % are rotten ones. How many eggs are rotten?
Solution:
Given that total number of eggs = 60
Number of eggs rotten = 16 2/3% of 60 eggs
= 16.66 % of 60 eggs
= (16.66/100) × 60
= 10 eggs
Therefore number of eggs rotten = 10
3. Rohit obtained 45 marks out of 80. What percent marks did he get?
Solution:
Given total number of marks = 80
Marks scored by Rohit = 45
Percentage obtained by Rohit = (45/80) × 100
= 56.25%
4. Mr Virmani saves 12% of his salary. If he receives Rs 15900 per month as salary, find his monthly expenditure.
Solution:
Given Mr Virmani’s salary per month = Rs. 15900
Mr Virmani’s savings = 12% of Rs. 15900
= (12/100) × 15900
= Rs. 1908
Mr Virmani’s monthly expenditure = salary – savings
= Rs. (15900 – 1908)
= Rs. 13992
5. A lawyer willed his 3 sons Rs 250000 to be divided into portions 30%, 45% and 25%. How much did each of them inherit?
Solution:
Given total amount with the lawyer = Rs. 250000
First son’s inheritance = 30% of 250000
= (30/100) × 250000
= 7500000/100
= Rs. 75000
Second son’s inheritance = 45% of 250000
= (45/100) × 250000
= 11250000/100
= Rs. 112500
Third son’s inheritance = 25% of 250000
= (25/100) × 250000
= 6250000/100
= Rs. 62500
6. Rajdhani College has 2400 students, 40% of whom are girls. How many boys are there in the college?
Solution:
Given total number of students in Rajdhani College = 2400
Number of girls = 40% of 2400
= (40/100) × 2400
= 96000/100
= 960
Number of boys = total number of students – number of girls
= 2400 – 960 = 1440 boys
7. Aman obtained 410 marks out of 500 in the CBSE XII examination, while his brother Anish got 536 marks out of 600 in the IX Class examination. Find whose performance is better.
Solution:
Given Aman’s marks in CBSE XII = 410/500
Percentage of marks obtained by Aman = (410/500) × 100
= 82%
Given that Anish’s marks in CBSE IX = 536/600
Percentage of marks obtained by Anish = (536/600) × 100
= 89.33%
Clearly, 89.33 > 82
Therefore, Anish’s performance is better than Aman’s
8. Rahim obtained 60 marks out of 75 in Mathematics. Find the percentage of marks obtained by Rahim in Mathematics.
Solution:
Given marks obtained by Rahim in Mathematics = 60/75
Percentage of marks obtained by Rahim = (60/75) × 100
= 80%
9. In an orchard, 16 2/3 % of the trees are apple trees. If the number of trees in the orchard is 240, find the number of other type of trees in the orchard.
Solution:
Let the number of apple trees be x
Number of trees in the orchard = 240
Number of apple trees = 16 2/3 %
According to the given condition, 16 (2/3) % of 240 = x
= 16.66 % of 240 = x
x = (16.66/100) × 240
x = 40 trees
Number of other types of trees = Total number of trees – number of apple trees
= 240 – 40
= 200 trees
10. Ram scored 553 marks out of 700, and Gita scored 486 marks out of 600 in science. Whose performance is better?
Solution:
Given marks scored by Ram = 553/700
Percentage of marks scored by Ram = (553/700) × 100
= 0.79 × 100 = 79%
Also given that marks scored by Gita = (486/600)
Percentage of marks scored by Gita = (486/600) × 100
= 0.81 × 100 = 81
Gita’s performance (81%) is better than Ram’s (79%).
11. Out of an income of Rs 15000, Nazima spends Rs 10200. What per cent of her income does she save?
Solution:
Given Nazima’s total income = Rs 15000
Amount Nazima spends = Rs 10200
Amount Nazima saves = 15000 – 10200
= Rs 4800
Percentage of income Nazima saves = (4800/15000) × 100
= 480000/15000
= 32%
Nazima saves 32% of her income.
12. 45% of the students in a school are boys. If the total number of students in the school is 880, find the number of girls in the school.
Solution:
Given total number of students in the school = 880
Number of boys in the school = 45% of 880
= (45/100) × 880
= 39600/100
Number of boys = 396
Number of girls in the school = total number of students – number of boys
= 880 – 396
Number of girls = 484
13. Mr. Sidhana saves 28% of his income. If he saves 840 per month, find his monthly income.
Solution:
Let Mr. Sidhana’s monthly income be x
Monthly savings of Mr. Sidhana’s = Rs 840
28% of x = Rs 840
⇒ (28/100) × x = Rs 840
⇒ 28x = Rs 84000
⇒ x = (84000/28) = Rs 3000
Mr. Sidhana’s monthly income = Rs 3000
14. In an examination, 8% of the students fail. What percentage of the students pass? If 1650 students appeared in the examination, how many passed?
Solution:
Given total number of students who appeared for the examination = 1650
Number of students who failed = 8% of 1650
= (8/100) ×1650
= (8 × 1650)/100
= 13200/100
Number of students failed = 132
Number of students passed = 1650 – 132
= 1518
Percentage of students passed = (1518/1650) × 100
= 0.92 × 100 = 92%
92% of the students passed the examination.
15. In an examination, 92% of the candidates passed, and 46 failed. How many candidates appeared?
Solution:
Let the total number of candidates be x
Number of candidates who failed = 46
Number of candidates who passed = 92% of x
According to the given condition
92% of x = x – 46
⇒ (92/100) x = x – 46
⇒ 92x = 100x – 4600
⇒ -8x = – 4600
⇒ x = 4600/8 = 575
Number of candidates who appeared for the examination = 575
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