NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Exercise 10.2 are provided here. The amount of surface which is occupied by a closed figure is its area. Students who follow the NCERT textbook of the current CBSE syllabus can make use of solutions prepared by subject matter experts to ace the exam with good scores. In order to obtain a hold on these concepts, students can refer to the NCERT Solutions Class 6 Maths Chapter 10 Mensuration Exercise 10.2.
NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Exercise 10.2
Access NCERT Solutions for Class 6 Maths Chapter 10: Mensuration Exercise 10.2
1. Find the areas of the following figures by counting squares.
(a) The figure contains only 9 fully-filled squares. Hence, the area of this figure will be 9 square units.
(b) The figure contains only 5 fully-filled squares. Hence, the area of this figure will be 5 square units.
(c) The figure contains 2 fully-filled squares and 4 half-filled squares. Hence, the area of this figure will be 4 square units.
(d) The figure contains only 8 fully-filled squares. Hence, the area of this figure will be 8 square units.
(e) The figure contains only 10 fully-filled squares. Hence, the area of this figure will be 10 square units.
(f) The figure contains only 2 fully-filled squares and 4 half-filled squares. Hence, the area of this figure will be 4 square units.
(g) The figure contains 4 fully-filled squares and 4 half-filled squares. Hence, the area of this figure will be 6 square units.
(h) The figure contains 5 fully-filled squares. Hence, the area of this figure will be 5 square units.
(i) The figure contains 9 fully-filled squares. Hence, the area of this figure will be 9 square units.
(j) The figure contains 2 fully-filled squares and 4 half-filled squares. Hence, the area of this figure will be 4 square units.
(k) The figure contains 4 fully-filled squares and 2 half-filled squares. Hence, the area of this figure will be 5 square units.
(l) From the given figure, we observe
| Covered area | Number | Area estimate (square units) |
| Fully-filled squares | 2 | 2 |
| Half-filled squares | – | – |
| More than half-filled squares | 6 | 6 |
| Less than half-filled squares | 6 | 0 |
Therefore, the total area = 2 + 6
= 8 square units
(m) From the given figure, we observe
| Covered area | Number | Area estimate (square units) |
| Fully-filled squares | 5 | 5 |
| Half-filled squares | – | – |
| More than half-filled squares | 9 | 9 |
| Less than half-filled squares | 12 | 0 |
Therefore, the total area = 5 + 9
= 14 square units
(n) From the given figure, we observe
| Covered area | Number | Area estimate (square units) |
| Fully-filled squares | 8 | 8 |
| Half-filled squares | – | – |
| More than half-filled squares | 10 | 10 |
| Less than half-filled squares | 9 | 0 |
Therefore, the total area = 8 + 10 = 18 square units
Also, explore –
NCERT Solutions for Class 6 Maths Chapter 10
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