NCERT Solutions for Class 6 Maths Chapter 6 Integers Exercise 6.2

NCERT Solutions for Class 6 Maths Chapter 6 Integers Exercise 6.2 explain the addition of integers and the addition of integers on a number in an easy manner. Students can access the PDF of the NCERT Solutions, which are answered in the best possible methods to help them solve problems in a better way. The set of examples which is present before the exercise problems helps students understand the method of solving problems. Students can refer to the Solutions provided at BYJU’S to prepare well for their exams.

NCERT Solutions for Class 6 Maths Chapter 6 Integers Exercise 6.2

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Access NCERT Solutions for Class 6 Chapter 6: Integers Exercise 6.2

1. Using the number line, write the integer which is

(a) 3 more than 5

(b) 5 more than –5

(c) 6 less than 2

(d) 3 less than –2

Solutions:

(a)

Hence, 8

(b)

Hence, 0

(c)

Hence, -4

(d)

Hence, -5

2. Use a number line and add the following integers.

(a) 9 + (–6)

(b) 5 + (–11)

(c) (–1) + (–7)

(d) (–5) + 10

(e) (–1) + (–2) + (–3)

(f) (–2) + 8 + (–4)

Solutions:

(a)

Hence, 3

(b)

Hence, -6

(c)

Hence, -8

(d)

Hence, 5

(e)

Hence, -6

(f)

Hence, 2

3. Add without using a number line.

(a) 11 + (–7)

(b) (–13) + (+18)

(c) (–10) + (+19)

(d) (–250) + (+150)

(e) (–380) + (–270)

(f) (–217) + (–100)

Solutions:

(a) 11 + (-7) = 4

(b) (-13) + (+18) = 5

(c) (-10) + (+19) = 9

(d) (-250) + (+150) = -100

(e) (-380) + (-270) = -650

(f) (-217) + (-100) = -317

4. Find the sum of

(a) 137 and – 354

(b) – 52 and 52

(c) – 312, 39 and 192

(d) – 50, – 200 and 300

Solutions:

(a) 137 and -354

(137) + (-354) = (137) + (-137) + (-217)

= 0 + (-217) [(137) + (-137) = 0]

= (-217)

= -217

(b) -52 and 52

(-52) + (+52) = 0 [(-a) + (+a) = 0]

(c) -312, 39 and 192

(-312) + (+39) + (+192) = (-231) + (-81) + (+39) + (+192)

= (-231) + (-81) + (+231)

= (-231) + (+231) + (-81)

= 0 + (-81) [(-a) + (+a) = 0]

= -81

(d) -50, -200 and 300

(-50) + (-200) + (+300) = (-50) + (-200) + (+200) + (+100)

= (-50) + 0 + (+100) [(-a) + (+a) = 0]

= (-50) + (+100)

= (-50) + (+50) + (+50)

= 0 + (+50) [(-a) + (+a) = 0]

= 50

5. Find the sum.

(a) (–7) + (–9) + 4 + 16

(b) (37) + (–2) + (–65) + (–8)

Solutions:

(a) (-7) + (-9) + 4 + 16

= (-7) + (-9) + 4 + (+7) + (+9)

= (-7) + (+7) + (-9) + (+9) + 4

= 0 + 0 + 4 [(-a) + (+a) = 0]

= 4

(b) (37) + (-2) + (-65) + (-8)

= (+37) + (-75)

= (+37) + (-37) + (-38)

= 0 + (-38) [(-a) + (+a) = 0]

= -38

Also, explore – 

NCERT Solutions for Class 6 Maths Chapter 6

NCERT Solutions for Class 6 Maths

NCERT Solutions for Class 6