 # NCERT Solutions For Class 6 Maths Ex 6.2

## NCERT Solutions For Class 6 Maths Ex 6.2 PDF Free Download

Addition of integers and addition of integers on a number are explained in an easy manner under the exercise 6.2. Students can access the PDF of solutions which are answered in the best possible way so that they can solve problems in offline mode as well. The set of examples which are present before the exercise problems helps students understand the method of solving problems. Students can make use of NCERT Solutions Class 6 Maths Chapter 6 Integers Exercise 6.2 PDF, which are provided here for free download.

## NCERT Solutions for Class 6 Chapter 6: Integers Exercise 6.2 Download PDF    ### Access NCERT Solutions for Class 6 Chapter 6: Integers Exercise 6.2

1. Using the number line write the integer which is:

(a) 3 more than 5

(b) 5 more than –5

(c) 6 less than 2

(d) 3 less than –2

Solutions:

(a) Hence, 8

(b) Hence, 0

(c) Hence, -4

(d) Hence, -5

2. Use number line and add the following integers:

(a) 9 + (–6)

(b) 5 + (–11)

(c) (–1) + (–7)

(d) (–5) + 10

(e) (–1) + (–2) + (–3)

(f) (–2) + 8 + (–4)

Solutions:

(a) Hence, 3

(b) Hence, -6

(c) Hence, -8

(d) Hence, 5

(e) Hence, -6

(f) Hence, 2

3. Add without using number line:

(a) 11 + (–7)

(b) (–13) + (+18)

(c) (–10) + (+19)

(d) (–250) + (+150)

(e) (–380) + (–270)

(f) (–217) + (–100)

Solutions:

(a) 11 + (-7) = 4

(b) (-13) + (+18) = 5

(c) (-10) + (+19) = 9

(d) (-250) + (+150) = -100

(e) (-380) + (-270) = -650

(f) (-217) + (-100) = -317

4. Find the sum of:

(a) 137 and – 354

(b) – 52 and 52

(c) – 312, 39 and 192

(d) – 50, – 200 and 300

Solutions:

(a) 137 and -354

(137) + (-354) = (317) + (-137) + (-217)

= 0 + (-217) [(317) + (-317) = 0]

= (-217)

= -217

(b) -52 and 52

(-52) + (+52) = 0 [(-a) + (+a) = 0]

(c) -312, 39 and 192

(-312) + (+39) + (+192) = (-231) + (-81) + (+39) + (+192)

= (-231) + (-81) + (+231)

= (-231) + (+231) + (-81)

= 0 + (-81) [(-a) + (+a) = 0]

= -81

(d) -50, -200 and 300

(-50) + (-200) + (+300) = (-50) + (-200) + (+200) + (+100)

= (-50) + 0 + (+100) [(-a) + (+a) = 0]

= (-50) + (+100)

= (-50) + (+50) + (+50)

= 0 + (+50) [(-a) + (+a) = 0]

= 50

5. Find the sum:

(a) (–7) + (–9) + 4 + 16

(b) (37) + (–2) + (–65) + (–8)

Solutions:

(a) (-7) + (-9) + 4 + 16

= (-7) + (-9) + 4 + (+7) + (+9)

= (-7) + (+7) + (-9) + (+9) + 4

= 0 + 0 + 4 [(-a) + (+a) = 0]

= 4

(b) (37) + (-2) + (-65) + (-8)

= (+37) + (-75)

= (+37) + (-37) + (-38)

= 0 + (-38) [(-a) + (+a) = 0]

= -38