NCERT Solutions For Class 6 Maths Ex 6.3

NCERT Solutions For Class 6 Maths Ex 6.3 PDF Free Download

The concepts which are covered in exercise 6.3 are subtraction of integers with the help of a number line. The exercise wise problems are solved in the best possible way with the aim of helping students perform better in the Class 6 Mathematics exam. These solutions are designed as per the NCERT textbook of the prescribed CBSE syllabus. Students who aspire to solve problems and improve their score in the exam can download NCERT Solutions Class 6 Maths Chapter 6 Integers Exercise 6.3 PDF from the links given below.

NCERT Solutions for Class 6 Chapter 6: Integers Exercise 6.3 Download PDF

 

ncert solutions class 6 maths chapter 6 ex 6.3
ncert solutions class 6 maths chapter 6 ex 6.3

 

Access NCERT Solutions for Class 6 Chapter 6: Integers Exercise 6.3

1. Find

(a) 35 – (20)

(b) 72 – (90)

(c) (-15) – (-18)

(d) (-20) – (13)

(e) 23 – (-12)

(f) (-32) – (-40)

Solutions:

(a) 35 – (20)

= 35 – 20

= 15

(b) 72 – (90)

= 72 – 90

= -18

(c) (-15) – (-18)

= -15 + 18

= 3

(d) (-20) – (13)

= -20 – 13

= -33

(e) 23 – (-12)

= 23 + 12

= 35

(f) (-32) – (-40)

= -32 + 40

= 8

2. Fill in the blanks with >, < or = sign.

(a) (–3) + (–6) ______ (–3) – (–6)

(b) (–21) – (–10) _____ (–31) + (–11)

(c) 45 – (– 11) ______ 57 + (– 4)

(d) (–25) – (–42) _____ (– 42) – (–25)

Solutions:

(a) (-3) + (-6) = -9

(-3) – (-6) = -3 + 6

= 3

-9 < 3

Therefore (-3) + (-6) > (-3) – (-6)

(b) -21 – (-10) = -21 + 10 = -11

-31 + (-11) = -42

-11 > -42

Therefore (-21) – (-10) > (-31) + (-11)

(c) 45 – (-11) 45 + 11 = 56

57 + (-4) = 57 – 4 = 53

56 > 53

Therefore 45 – (-11) > 57 + (-4)

(d) (-25) – (-42) = -25 + 42 = 17

-42 – (-25) = -42 + 25 = -17

17 > -17

Therefore (-25) – (-42) > (-42) – (-25)

3. Fill in the blanks.

(a) (–8) + _____ = 0

(b) 13 + _____ = 0

(c) 12 + (–12) = ____

(d) (–4) + ____ = –12

(e) ____ – 15 = – 10

Solutions:

(a) (-8) + 8 = 0

(b) 13 + (-13) = 0

(c) 12 + (-12) = 0

(d) (-4) + (-8) = -12

(e) 5 – 15 = -10

4. Find

(a) (–7) – 8 – (–25)

(b) (–13) + 32 – 8 – 1

(c) (–7) + (–8) + (–90)

(d) 50 – (–40) – (–2)

Solutions:

(a) (-7) – 8 – (-25) = -7 -8 + 25

= -15 + 25

= 10

(b) (-13) + 32 – 8 – 1 = -13 + 32 – 8 – 1

= 32 – 22

= 10

(c) (-7) + (-8) + (-90) = -7 – 8 – 90

= – 105

(d) 50 – (-40) – (-2) = 50 + 40 + 2

= 92


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