NCERT Solutions For Class 6 Maths Chapter 6 Integers Exercise 6.3

The concepts which are covered in NCERT Solutions For Class 6 Maths Chapter 6 Integers Exercise 6.3 are subtraction of integers with the help of a number line. The exercise wise problems are solved in the best possible way with the aim of helping students perform better in the Class 6 Mathematics exam. These NCERT Solutions Class 6 Maths are designed as per the NCERT textbook of the prescribed CBSE syllabus. Students who aspire to solve all the problems and improve their score in the exam can download these solutions to understand the problem solving methods of different types of questions.

NCERT Solutions for Class 6 Chapter 6: Integers Exercise 6.3 Download PDF

 

ncert solutions class 6 maths chapter 6 ex 6.3
ncert solutions class 6 maths chapter 6 ex 6.3

 

Access NCERT Solutions for Class 6 Chapter 6: Integers Exercise 6.3

1. Find

(a) 35 – (20)

(b) 72 – (90)

(c) (-15) – (-18)

(d) (-20) – (13)

(e) 23 – (-12)

(f) (-32) – (-40)

Solutions:

(a) 35 – (20)

= 35 – 20

= 15

(b) 72 – (90)

= 72 – 90

= -18

(c) (-15) – (-18)

= -15 + 18

= 3

(d) (-20) – (13)

= -20 – 13

= -33

(e) 23 – (-12)

= 23 + 12

= 35

(f) (-32) – (-40)

= -32 + 40

= 8

2. Fill in the blanks with >, < or = sign.

(a) (–3) + (–6) ______ (–3) – (–6)

(b) (–21) – (–10) _____ (–31) + (–11)

(c) 45 – (– 11) ______ 57 + (– 4)

(d) (–25) – (–42) _____ (– 42) – (–25)

Solutions:

(a) (-3) + (-6) = -9

(-3) – (-6) = -3 + 6

= 3

-9 < 3

Therefore (-3) + (-6) > (-3) – (-6)

(b) -21 – (-10) = -21 + 10 = -11

-31 + (-11) = -42

-11 > -42

Therefore (-21) – (-10) > (-31) + (-11)

(c) 45 – (-11) 45 + 11 = 56

57 + (-4) = 57 – 4 = 53

56 > 53

Therefore 45 – (-11) > 57 + (-4)

(d) (-25) – (-42) = -25 + 42 = 17

-42 – (-25) = -42 + 25 = -17

17 > -17

Therefore (-25) – (-42) > (-42) – (-25)

3. Fill in the blanks.

(a) (–8) + _____ = 0

(b) 13 + _____ = 0

(c) 12 + (–12) = ____

(d) (–4) + ____ = –12

(e) ____ – 15 = – 10

Solutions:

(a) (-8) + 8 = 0

(b) 13 + (-13) = 0

(c) 12 + (-12) = 0

(d) (-4) + (-8) = -12

(e) 5 – 15 = -10

4. Find

(a) (–7) – 8 – (–25)

(b) (–13) + 32 – 8 – 1

(c) (–7) + (–8) + (–90)

(d) 50 – (–40) – (–2)

Solutions:

(a) (-7) – 8 – (-25) = -7 -8 + 25

= -15 + 25

= 10

(b) (-13) + 32 – 8 – 1 = -13 + 32 – 8 – 1

= 32 – 22

= 10

(c) (-7) + (-8) + (-90) = -7 – 8 – 90

= – 105

(d) 50 – (-40) – (-2) = 50 + 40 + 2

= 92


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