# Ncert Solutions For Class 8 Maths Ex 4.4

## Ncert Solutions For Class 8 Maths Chapter 4 Ex 4.4

Question 1:

AB = 4cm

BC = 5cm

CD = 4.5cm

B$\angle B$ = 60$60^{\circ}$

C$\angle C$ = 90$90^{\circ}$

PQ = 3.5cm

QR = 3cm

RS = 4cm

Q$\angle Q$ = 75$75^{\circ}$

R$\angle R$ = 120$120^{\circ}$

(i) Draw a rough sketch of the given quadrilateral as given below.

(ii) Draw a line segment AB of 4 cm and mark an angle of 60$60^{\circ}$ at point B. Cut a line segment BC of 5 cm from its ray as vertex B is 6 cm away from vertex B.

(iii) Draw an angle of 90$90^{\circ}$ at point C. Cut a line segment DC of 4.5 cm from its ray as vertex C is 4.5 cm away from vertex C.

(iv) Join A to D.

Thus we get the required quadrilateral ABCD.

(i) Draw a rough sketch of the given quadrilateral as given below.

(ii) Draw a line segment QR of 4 cm and point R make an angle of 120$120^{\circ}$. Cut a line segment RS of 5 cm from its ray as vertex S is 5 cm away from vertex R.

(iii) Draw an angle of 75$75^{\circ}$ at point Q. Cut a line segment QP of 4.5 cm from its ray as vertex P is 4.5 cm away from vertex Q.

(iv) Join P to S.

Thus we get the required quadrilateral PQRS.