The NCERT Solutions for Class 8 Maths enhance students’ problem-solving skills by presenting topics with focused and engaging activities that strengthen their Maths concepts. Each question of exercise 4.5 in NCERT Class 8 Maths Solutions has been carefully solved for the students to understand from an examination point of view.
Class 8 Maths Chapter 4 – Practical Geometry Exercise 4.5 Questions and answers help the students to understand the construction of a quadrilateral in some special cases. These NCERT Solutions are prepared by the subject experts at BYJU’S in a step-by-step approach.
NCERT Solutions for Class 8 Maths Chapter 4 – Practical Geometry Exercise 4.5
Access Other Exercise Solutions of Class 8 Maths Chapter 4 – Practical Geometry
Exercise 4.1 Solutions 1 Question
Exercise 4.2 Solutions 1 Question
Exercise 4.3 Solutions 1 Question
Exercise 4.4 Solutions 1 Question
Access Answers to NCERT Class 8 Maths Chapter 4 – Practical Geometry Exercise 4.5 Page Number 60
Draw the following:
1. The square READ with RE = 5.1 cm.
Solution:
All the sides of a square are of the same measure, and also, all the interior angles of a square measure 90º. So the given square READ can be drawn as follows.
Rough Figure:
(1) Draw a line segment RE of 5.1 cm and an angle of 90º at points R and E.
(2) As vertex A and D are 5.1 cm away from vertex E and R, respectively, cut line segments EA and RD, each of 5.1 cm from these rays.
(3) Join D to A.
READ is the required square.
2. A rhombus whose diagonals are 5.2 cm and 6.4 cm long.
Solution:
In a rhombus, diagonals bisect each other at 90º. Therefore, the given rhombus ABCD can be drawn as follows.
Rough Figure:
(1) Draw a line segment AC of 5.2 cm and draw its perpendicular bisector. Let it intersect the line segment AC at point O.
(2) Draw arcs of 6.4/2 = 3.2 on both sides of this perpendicular bisector. Let the arcs intersect the perpendicular bisector at points B and D.
(3) Join points B and D with points A and C.
ABCD is the required rhombus.
3. A rectangle with adjacent sides of length 5 cm and 4 cm.
Solution:
Opposite sides of a rectangle have lengths of the same measure, and also, all the interior angles of a rectangle measure 90º. The given rectangle ABCD may be drawn as follows:
Rough figure:
(1) Draw a line segment AB of 5 cm and an angle of 90º at points A and B.
(2) As vertex C and D are 4 cm away from vertex B and A, respectively, cut line segments AD and BC, each of 4 cm, from these rays.
(3) Join D to C.
ABCD is the required rectangle.
4. A parallelogram OKAY where OK = 5.5 cm and KA = 4.2 cm.
Solution:
Opposite sides of a parallelogram are equal and parallel to each other. The given parallelogram OKAY can be drawn as follows:
Rough Figure:
(1) Draw a line segment OK of 5.5 cm and a ray at point K at a convenient angle.
(2) Draw a ray at point O parallel to the ray at K. As the vertices A and Y are 4.2 cm away from the vertices K and O, respectively, cut line segments KA and OY, each of 4.2 cm, from these rays.
(3) Join Y to A.
OKAY is the required rectangle.
Exercise 4.5 of NCERT Solutions for Class 8 Maths Chapter 4 – Practical Geometry is based on the following topics:
- Constructing a Quadrilateral
- Some special cases
Also, explore –Â
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