In this article, we shall learn how to solve Quadratic Equations in bank exams.
Quadratic equation is one of the most complex and tricky parts of Quantitative Aptitude where candidates generally make silly mistakes if they do not focus during their bank exam preparation.
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As a result, there are some tricks and strategies which are essential to solve a quadratic equation. Bank exams require accuracy in the allotted time during the main exam so shortcut tricks are important for an aspirant to quickly solve a particular bank exam question.
The numerical ability section is where the candidates can score well by practising well within a given time using more tricks during their bank exam preparation.
Weightage of Quadratic Equation in Bank Exams
Priority | Nature of expected questions | Weightage |
1 | Maintaining accuracy, problems that can be solved easily, easy to manage time, scoring in nature | 0-5 |
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Stepwise Tips to practice a Quadratic Equation:
- Firstly the candidate needs to note down twenty sums related to the quadratic equation on a page.
- Then ten sums are to be solved using basic formula.
- To solve these sums using a stopwatch will help in time management.
- The next step is to evaluate the time taken and analyse the performance.
- The remaining ten questions are to be solved next by applying the shortcut tricks.
- The time taken should be noted carefully.
- This will surely have a difference from the time taken while solving the first ten questions.
- Practice is the key to master this topic of the Quantitative Aptitude section.
To explore theÂ SBI Clerk Prelims Quantitative Syllabus, check at the linked article.
The basic equation of quadratic equation is \(ax^{2}+ bx+c =0\) where this equation is equal to zero and a,b,c are constants. The quadratic equation only holds the power of x where x is also known as a non-negative integer.
For example: \(6x^{2} + 11x +3= 0\)
Solution: In this equation 6 is the coefficient of \(x^{2}\)
11 is the coefficient of x and 3 is constant. The easiest way is to solve this through the middle term break method.
First step:Â To multiply \((+6)\times (+3)\) = +18
Second step: +18 is to be broken into two parts in such a way that their addition results in the middle term that is 11 where \(9 + 2 = 11\) and product of these factors are 18.
Third step: To change the sign of the factors where +9 = -9 and +2 =-2 and this has to be divided by coefficient of \(x^{2}\). Therefore, \(-9/6 = -3/2\) and \(-2/6 = -1/3\).
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Top 3 Tips to solve Quadratic Equations in Bank Exams
The major three ways to solve the problems on the Quadratic Equation are as follows:
- To factor the Quadratic Equation- Here all the same terms are to be combined and to the one side of the equation in such a way that there remains nothing on the other side. Once it has no remaining terms we can write zero.
For example: \(3x^{2} – 8x -4 = 3x + x^{2}\) \(4x^{2} – 11x – 4=0\) The second step is to factor the equation so that there is a set each through the middle term break method. The last part is to separate each factor set to zero.
For example: \((3x+1)(x-4)=0\) - To use the formula- The sums can be solved through the formula \(\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}\) and solve putting the equations in this.
- To complete the square- This process is bit complex while the other two are easy to solve.
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We hope the above-mentioned shortcut tricks and strategies will help the candidates during their bank exam preparation for Quadratic Equations. All the candidate needs to do is practice with determination and hard work to crack the bank exams successfully.
Important Bank Exams Information:
Both IPBS and SBI exams have the Quadratic Equations topic in the Quantitative Aptitude section of the Preliminary and Mains exams. Being a scoring topic, it is advisable for candidates to practice efficiently and earn a full score on this topic during their respective bank examination.