 # Logical Reasoning Questions

Being an integral section in the CAT exam, logical reasoning gives a hard time to many of the CAT test-takers. The logical reasoning section demands the candidates to be extremely focused while solving. The logical reasoning section mainly includes questions related to arrangements (simple and complex). So, to help the CAT exam 2022 aspirants prepare properly, here is a brief explanation with an illustration of the logical reasoning section.

## Logical Reasoning Questions and Solutions:

Sequencing in a line:

A formal linear arrangement is one that emphasizes lines and movement in an arrangement.

These types of questions could be based on “Seating Arrangement”.

Four people in line: The Examples can remain the same

## Let’s solve an actual CAT 2019 Logical Reasoning Set:

The following table represents the addition of two six-digit numbers given in the first and the second rows, while the sum is given in the third row. In the representation, each of the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 has been coded with one letter among A, B, C, D, E, F, G,H, J, K, with distinct letters representing distinct digits. Q1. Which digit does the letter A represent?

Ans. 1

Q2. Which digit does the letter B represent?

Ans. 9

Q3. Which among the digits 3, 4, 6 and 7 cannot be represented by the letter D?

Ans. 7

Q4. Which among the digits 4, 6, 7 and 8 cannot be represented by the letter G?

Ans. 6

Solution –

F + F = F.

This implies that F has to be 0. Since all the digits are less than 10, the maximum sum of any two letters will be 17 (i.e. 9 + 8).

Therefore, a maximum of 1 can be carried over to the digits place on the left. In the ten thousands place, either the units digit of H + H = F or the units digit of H + H + 1 = F.

It cannot be H + H + 1 because 2H + 1 is an odd number and the units digit of that cannot be 0. From this, we can infer that the units digit of 2H must be 0.

This implies that H = 5. Sum of both the 6-digit numbers is a 7-digit number. This implies that the leftmost digit in the 7-digit number has to be 1. Therefore. A = 1.

Since H = 5, H + H = 10. This means that B + A + 1 = AA = 10A + A. A = 1. Therefore. B = 9.

In the hundreds place the units place of the sum A + F is C. Now A = 1 and F = 0.

But C cannot be 1. Hence, C has to be A + 1, i.e. C = 2. Therefore, G + K should be greater than 10.

The units digit of the sum of G + K is 1. This implies that G and K are either 3 and 8 or 4 and 7. not necessarily in that order.

We now have the following:

 9 5 1 1 G 0 1 5 J 0 K 0 1 1 0 G 2 1 0

Since G is a single digit, J + 1 is less than 9.

If J = 3. G = 4 and K = 7. In that case. D and E will be 6 and 8. not necessarily in that order.

If j = 4. G = 5. which is not possible because H = 5 and each letter has a distinct number.

If J = 6. G = 7 and K = 4. In that case. D and E will be

3 and 8. not necessarily in that order.

If j = 7. G = 8 and K = 3. In that case, D and E will be

4 and 6 not necessarily in that order.

If J = 8, G = 9, which is not possible because B = 9 and each letter has a distinct number.

Visit logical reasoning for CAT to learn more about the section and other important topics easily. Also, get various practice questions and sample questions of the LR section to prepare properly.

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