 # RD Sharma Solutions for Class 8 Chapter 19 Visualising Shapes Exercise 19.2

### RD Sharma Class 8 Solutions Chapter 19 Ex 19.2 PDF Free Download

Exercise 19.2 of Chapter 19, mainly deals with visualisation of 3-D shapes through nets. The problems are solved in a simple and precise manner by a set of expert faculty team at BYJU’S. The solutions are designed stepwise as per the marks allotted for each step in the exam pattern, so following the steps is a must. Students can achieve their goals only by practising regularly. RD Sharma Class 8 Solutions which is a very useful study material helps students in their exam preparation. The pdf can be downloaded from the available links mentioned below.

## Download the Pdf of RD Sharma for Class 8 Maths Exercise 19.2 Chapter 19 Visualising Shapes     ### Access answers to RD Sharma Maths Solutions For Class 8 Exercise 19.2 Chapter 19 Visualising Shapes

1. Which among of the following are nets for a cube? Solution:

Figure (iv), (v), (vi) are the nets for a cube.

2. Name the polyhedron that can be made by folding each net: Solution:

(i) From figure (i), a Square pyramid can be made by folding each net.

(ii) From figure (ii), a Triangular prism can be made by folding each net.

(iii) From figure (iii), a Triangular prism can be made by folding each net.

(iv) From figure (iv), a Hexagonal prism can be made by folding each net.

(iv) From figure (v), a Hexagonal pyramid can be made by folding each net.

(v) From figure (vi), a Cube can be made by folding each net.

3. Dice are cubes where the numbers on the opposite faces must total 7. Which of the following are dice? Solution:

Figure (i), is a dice. Since the sum of numbers on opposite faces is 7 (3 + 4 = 7 and 6 + 1 = 7).

4. Draw nets for each of the following polyhedrons: Solution:

(i) The net pattern for cube is (ii) The pattern for triangular prism is (iii) The net pattern for hexagonal prism is (iv) The net pattern for pentagonal pyramid is 5. Match the following figures: Solution:

(a)-(iv) Because multiplication of numbers on adjacent faces are equal, where 6×4 = 24 and 4×4 = 16

(b)-(i) Because multiplication of numbers on adjacent faces are equal, where 3×3 = 9 and 8×3 = 24

(c)-(ii) Because multiplication of numbers on adjacent faces are equal, where 6×4 = 24 and 6×3 = 18

(d)-(iii) Because multiplication of numbers on adjacent faces are equal, where 3×3 = 9 and 3×9 = 27