 # RD Sharma Solutions for Class 8 Chapter 3 - Squares and Square Roots Exercise 3.9

### RD Sharma Class 8 Solutions Chapter 3 Ex 3.9 PDF Free Download

Exercise 3.9 of RD Sharma Solutions for the Class 8 Maths Chapter 3, Squares and Square Roots. Students can refer and download from the links provided below. Our expert team at BYJU’S have solved the RD Sharma Solutions for Class 8 that help students practice the problems without any obstacles. Exercise 3.9 of Class 8 is about finding the approximate values of square roots by using square root tables.

Practice RD Sharma Solutions for Class 8 for better understanding of the concepts, which help students obtain high marks in their examination.

## Download the pdf of RD Sharma For Class 8 Maths Chapter 3 Squares and Square Roots     ### Access other Exercises of RD Sharma Solutions for Class 8 Maths Chapter 3 Squares and Square Roots

Exercise 3.1 Solutions 13 Questions

Exercise 3.2 Solutions 15 Questions

Exercise 3.3 Solutions 7 Questions

Exercise 3.4 Solutions 16 Questions

Exercise 3.5 Solutions 12 Questions

Exercise 3.6 Solutions 5 Questions

Exercise 3.7 Solutions 18 Questions

Exercise 3.8 Solutions 5 Questions

### Access Answers to RD Sharma Solutions for Class 8 Maths Exercise 3.9 Chapter 3 Squares and Square Roots

Using square root table, find the square roots of the following:
1. 7

Solution:

From square root table we know,

Square root of 7 is:

√7 = 2.645

∴ The square root of 7 is 2.645

2. 15

Solution:

From square root table we know,

Square root of 7 is:

15 = 3.8729

∴ The square root of 15 is 3.873

3. 74

Solution:

From square root table we know,

Square root of 74 is:

74 = 8.6023

∴ The square root of 74 is 8.602

4. 82

Solution:

From square root table we know,

Square root of 82 is:

82 = 9.0553

∴ The square root of 82 is 9.055

5. 198

Solution:

From square root table we know,

Square root of 198 is:

198 = 14.0712

∴ The square root of 198 is 14.071

6. 540

Solution:

From square root table we know,

Square root of 540 is:

540 = 23.2379

∴ The square root of 540 is 23.24

7. 8700

Solution:

From square root table we know,

Square root of 8700 is:

8700 = 93.2737

∴ The square root of 8700 is 93.27

8. 3509

Solution:

From square root table we know,

Square root of 3509 is:

3509 = 59.2368

∴ The square root of 3509 is 59.235

9. 6929

Solution:

From square root table we know,

Square root of 6929 is:

6929 = 83.2406

∴ The square root of 6929 is 83.239

10. 25725

Solution:

From square root table we know,

Square root of 25725 is:

25725 = 160.3901

∴ The square root of 25725 is 160.41

11. 1312.

Solution:

From square root table we know,

Square root of 1312 is:

1312 = 36.2215

∴ The square root of 1312 is 36.22

12. 4192

Solution:

From square root table we know,

Square root of 4192 is:

4192 = 64.7456

∴ The square root of 4192 is 64.75

13. 4955

Solution:

From square root table we know,

Square root of 4955 is:

4955 = 70.3917

∴ The square root of 4955 is 70.39

14. 99/144

Solution:

From square root table we know,

Square root of 99/144 is:

(99/144) = 0.82915

∴ The square root of 99/144 is 0.829

15. 57/169

Solution:

From square root table we know,

Square root of 57/169 is:

√(57/169) = 0.58207

∴ The square root of 57/169 is 0.581

16. 101/169

Solution:

From square root table we know,

Square root of 101/169 is:

√(101/169) = 0.77306

∴ The square root of 57/169 is 0.773

17. 13.21

Solution:

From square root table we know,

Square root of 13.21 is:

√13.21 = 3.6345

∴ The square root of 13.21 is 3.635

18. 21.97

Solution:

From square root table we know,

Square root of 21.97 is:

√21.97 = 4.6872

∴ The square root of 21.97 is 4.6872

19. 110

Solution:

From square root table we know,

Square root of 110 is:

√110 = 10.4880

∴ The square root of 110 is 10.488

20. 1110

Solution:

From square root table we know,

Square root of 1110 is:

√1110 = 33.3166

∴ The square root of 1110 is 33.317

21. 11.11

Solution:

From square root table we know,

Square root of 11.11 is:

√11.11 = 3.33316

∴ The square root of 11.11 is 3.333

22. The area of a square field is 325m2. Find the approximate length of one side of the field.

Solution:

We know that the given area of the field = 325 m2

To find the approximate length of the side of the field we will have to calculate the square root of 325

√325 = 18.027 m

∴ The approximate length of one side of the field is 18.027 m

23. Find the length of a side of a square, whose area is equal to the area of a rectangle with sides 240 m and 70 m.

Solution:

We know that from the question,

Area of square = Area of rectangle

Side2 = 240 × 70

Side = √(240 × 70)

= √(10×10×2×2×2×3×7)

= 20√(42)

= 20 × 6.48

= 129.60 m

∴ The length of side of the square is 129.60 m

## RD Sharma Solutions for Class 8 Maths Exercise 3.9 Chapter 3 – Squares and Square Roots

Exercise 3.9 of RD Sharma Solutions for Chapter 3 Squares and Square Roots, this exercise mainly deals with the concepts related to finding the approximate values of square roots by using square root tables.

The students can solve problems of RD Sharma textbook for Class 8 using the solutions as reference material. This mainly improves confidence among students in solving tricky and lengthy problems easily. The PDF is easily accessible by the students which help in speeding up their exam preparation.