RD Sharma Solutions for Class 8 Maths Exercise 7.2 Chapter 7 Factorization are available here. The subject-matter experts at BYJU’S have formulated solutions based on the marks allotted to each step of a problem. The main objective is to help students in solving problems, which in turn, makes the subject easier to understand. Our experts have provided chapter-wise solutions which help students perform well in the annual exam. Students can download RD Sharma Solutions from the links given below.
In Exercise 7.2 of Chapter 7, Factorization, we will study the concepts based on the factorization of algebraic expressions when a common monomial factor occurs in each term.
RD Sharma Solutions for Class 8 Maths Exercise 7.2 Chapter 7 Factorization
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EXERCISE 7.2 PAGE NO: 7.5
Factorize the following:
1. 3x – 9
Solution:
The greatest common factor in the given two terms is 3
3x – 9
3 (x – 3)
2. 5x – 15x2
Solution:
The greatest common factor in the given two terms is 5x
5x – 15x2
5x (1 – 3x)
3. 20a12b2 – 15a8b4
Solution:
The greatest common factor in the given two terms is 5a8b2
20a12b2 – 15a8b4
5a8b2 (4a4 – 3b2)
4. 72x6y7 – 96x7y6
Solution:
The greatest common factor in the given two terms is 24x6y6
72x6y7 – 96x7y6
24x6y6 (3y – 4x)
5. 20x3 – 40x2 + 80x
Solution:
The greatest common factor in the given three terms is 20x
20x3 – 40x2 + 80x
20x (x2 – 2x +4)
6. 2x3y2 – 4x2y3 + 8xy4
Solution:
The greatest common factor in the given three terms is 2xy2
2x3y2 – 4x2y3 + 8xy4
2xy2 (x2 – 2xy + 4y2)
7. 10m3n2 + 15m4n – 20m2n3
Solution:
The greatest common factor in the given three terms is 5mn2
10m3n2 + 15m4n – 20m2n3
5m2n (2mn + 3m2 – 4n2)
8. 2a4b4 – 3a3b5 + 4a2b5
Solution:
The greatest common factor in the given three terms is a2b4
2a4b4 – 3a3b5 + 4a2b5
a2b4 (2a2 – 3ab + 4b)
9. 28a2 + 14a2b2 – 21a4
Solution:
The greatest common factor in the given three terms is 7a2
28a2 + 14a2b2 – 21a4
7a2 (4a + 2b2 – 3a2)
10. a4b – 3a2b2 – 6ab3
Solution:
The greatest common factor in the given three terms is ab
a4b – 3a2b2 – 6ab3
ab (a3 – 3ab – 6b2)
11. 2l2mn – 3lm2n + 4lmn2
Solution:
The greatest common factor in the given three terms is lmn
2l2mn – 3lm2n + 4lmn2
lmn (2l – 3m + 4n)
12. x4y2 – x2y4 – x4y4
Solution:
The greatest common factor in the given three terms is x2y2
x4y2 – x2y4 – x4y4
x2y2 (x2 – y2 – x2y2)
13. 9x2y + 3axy
Solution:
The greatest common factor in the given three terms is 3xy
9x2y + 3axy
3xy (3x + a)
14. 16m – 4m2
Solution:
The greatest common factor in the given two terms is 4m
16m – 4m2
4m (4 – m)
15. -4a2 + 4ab – 4ca
Solution:
The greatest common factor in the given three terms is – 4a
-4a2 + 4ab – 4ca
-4a (a – b + c)
16. x2yz + xy2z + xyz2
Solution:
The greatest common factor in the given three terms is xyz
x2yz + xy2z + xyz2
xyz (x + y +z)
17. ax2y + bxy2 + cxyz
Solution:
The greatest common factor in the given three terms is xy
ax2y + bxy2 + cxyz
xy (ax + by + cz)
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