We have studied factorization in the previous chapter, and we will implement it here in the form of the division of polynomials by using factorization. In Exercise 8.6 of RD Sharma Solutions for Class 8 Chapter 8 Division of Algebraic Expressions, we will learn the division of polynomials in one and two variables by factorizing the dividend and divisor and then cancelling out the common factors from the numerator and denominator. Students can refer to the RD Sharma textbook to gain knowledge of the subject well. To get a better understanding of the concepts, students can download and practise the RD Sharma Solutions, which is prepared by the subject experts at BYJU’S.
RD Sharma Solutions for Class 8 Maths Exercise 8.6 Chapter 8 Division of Algebraic Expressions
Access Answers to RD Sharma Solutions for Class 8 Maths Exercise 8.6 Chapter 8 Division of Algebraic Expressions
EXERCISE 8.6 PAGE NO: 8.17
Divide:
1. x2 – 5x + 6 by x – 3
Solution:
We have,
(x2 – 5x + 6) / (x – 3)
Let us perform long division method,
∴ the Quotient is x – 2
2. ax2 – ay2 by ax+ay
Solution:
We have,
(ax2 – ay2)/ (ax+ay)
(ax2 – ay2)/ (ax+ay) = (x – y) + 0/(ax+ay)
= (x – y)
∴ the answer is (x – y)
3. x4 – y4 by x2 – y2
Solution:
We have,
(x4 – y4)/ (x2 – y2)
(x4 – y4)/ (x2 – y2) = x2 + y2 + 0/(x2 – y2)
= x2 + y2
∴ the answer is (x2 + y2)
4. acx2 + (bc + ad)x + bd by (ax + b)
Solution:
We have,
(acx2 + (bc + ad) x + bd) / (ax + b)
(acx2 + (bc + ad) x + bd) / (ax + b) = cx + d + 0/ (ax + b)
= cx + d
∴ the answer is (cx + d)
5. (a2 + 2ab + b2) – (a2 + 2ac + c2) by 2a + b + c
Solution:
We have,
[(a2 + 2ab + b2) – (a2 + 2ac + c2)] / (2a + b + c) [(a2 + 2ab + b2) – (a2 + 2ac + c2)] / (2a + b + c) = b – c + 0/(2a + b + c)= b – c
∴ the answer is (b – c)
6. 1/4x2 – 1/2x – 12 by 1/2x – 4
Solution:
We have,
(1/4x2 – 1/2x – 12) / (1/2x – 4)
Let us perform long division method,
∴ the Quotient is x/2 + 3
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