Home / United States / Math Classes / 7th Grade Math / Multiplication of Rational Numbers
Rational numbers include all natural numbers, whole numbers, and integers. We have learned how to perform multiplication operations on natural numbers, whole numbers, and integers. Here we will apply the same concept to find the product of two rational numbers. ...Read MoreRead Less
A fraction with integer values both in the numerator and the denominator (the denominator is not zero) is a rational number. When two rational numbers are multiplied, a third rational number is produced. Use the same rules for signs as you did for integers when multiplying rational numbers. When the signs of the two numbers that are being multiplied are the same, the product is positive and when the signs are different, the product is negative.
For example, \(\frac{-1}{7}\times \frac{1}{3}=\frac{-1}{21}\)
Example 1: Find: -2.6 x 3.6
Solution:
2.6 (1 decimal place)
x 3.6 (+1 decimal place)
____
156
780
____
9.36 (2 decimal places)
Example 2: Find: -0.6 x 6.3
Solution:
6.3 (1 decimal place)
x 0.6 (+1 decimal place)
____
3.78 (2 decimal places)
So, -0.6 x 6.3 = -3.78
Example 3: Find \(-\frac{4}{5}\left(-\frac{2}{3}\right)=?\)
Solution:
\(\frac{4}{5}\left(\frac{2}{3}\right)=\frac{4 × 2}{5 × 3}\)
\(=\frac{8}{15}\) (Multiplying the numerators and the denominators)
So, \(-\frac{4}{5}\left(-\frac{2}{3}\right)=\frac{8}{15}\)
Example 4: Find \(-\frac{1}{2}\left(-5\frac{2}{3}\right)=?\)
Solution:
\(\frac{1}{2}\left(5\frac{2}{3}\right)=\frac{1}{2}\left(\frac{17}{3}\right)\) (Writing the mixed number as an improper fraction)
\(=\frac{17}{6}\) (Multiplying the numerators and the denominators)
So, \(-\frac{1}{2}\left(-5\frac{2}{3}\right)=\frac{17}{6}\)
Example 5: Find \(\left(-\frac{1}{6}\times \frac{4}{5}\right)\times(-6)\times \left(-\frac{1}{2}\right)=?\)
Solution: To find the product, we can use the properties of multiplication.
\(\left(-\frac{1}{6}\times \frac{4}{5}\right)\times (-6)\times \left(-\frac{1}{2}\right)=-6\times \left(-\frac{1}{6} \times \frac{4}{5}\right)\times \left(-\frac{1}{2}\right)\) (Using the commutative property of multiplication)
\(=\left[-6\times \left(-\frac{1}{6}\right)\right]\times \frac{4}{5}\times \left(-\frac{1}{2}\right)\) (Using the associative property of multiplication)
\(=1\times \frac{4}{5}\times \left(-\frac{1}{2}\right)\) (Using the multiplicative inverse property)
\(=\frac{4}{5}\times \left(-\frac{1}{2}\right)\) (Using the multiplication property of one)
\(=\frac{4\times (-1)}{5\times 2}\) (Using multiplication and dividing the common factor 2)
\(=\frac{-2}{5} \) or \(=-\frac{2}{5}\) (Simplified)
Example 6: Find \(-\frac{4}{5}\times 7\frac{3}{5}\times \frac{5}{4}=?\)
Solution: To find the product, we can use the properties of multiplication.
\(-\frac{4}{5}\times 7\frac{3}{5}\times \frac{5}{4}=-\frac{4}{5}\times \frac{5}{4}\times 7\frac{3}{5}\) (Using the commutative property of multiplication)
\(=\left(-\frac{4}{5}\times \frac{5}{4}\right)\times 7\frac {3}{5}\) (Using the associative property of multiplication)
\(=-1\times 7\frac{3}{5}\) (Using the multiplicative inverse property)
\(=-7\frac{3}{5}\) (Using the multiplication property of one)
\(=-\frac{35+3}{5}\) (Writing the mixed number as an improper fraction)
\(=-\frac{38}{5}\)
Example 7: Katie has a lemonade stall. Each lemonade costs $1.5. She sells 1 lemonade every hour. She has been selling lemonade for 4 hours. How much has she earned so far?
Solution:
Cost of 1 lemonade = $1.5
Number of hours worked = 3.5
She sells a lemonade every hour
Total amount earned = 1.5 × 4
= 6
Amount earned so far is $6.
When we multiply a rational number by its inverse, we get 1 as the answer. For example,
\(\left(\frac{1}{2}\right)\times \left(\frac{2}{1}\right)=1\)
The commutative property of multiplication of rational numbers states that even if you change the order in which the rational numbers are multiplied, it does not affect the product. In other words, the product remains the same.
The associative property of multiplication of rational numbers states that the order in which the numbers are grouped for multiplication does not affect the result.