RD Sharma Solutions Class 6 Geometrical Constructions Exercise 19.4

RD Sharma Solutions Class 6 Chapter 19 Exercise 19.4

RD Sharma Class 6 Solutions Chapter 19 Ex 19.4 PDF Download

Exercise 19.4

Q.1 Construct the following angles with the help of protractor :

450, 670, 380, 1100, 1790, 980, 840.

Soln.1 :

450

We draw a ray OA.

We place the protractor on OA such that its center coincides with the point 0 and the diameter of the protractor coincides with OA.

We mark a point B against the mark of 45° on the protractor.

We remove the protractor and draw OB. \(\angle AOB\) is the required angle of 45°.

Similarly, we draw the angles 670, 380, 1100, 1790, 980 and 840.

C:\Users\Administrator\Desktop\Capture33.PNG C:\Users\Administrator\Desktop\Capture34.PNG

C:\Users\Administrator\Desktop\Capture36.PNG C:\Users\Administrator\Desktop\Capture35.PNG

C:\Users\Administrator\Desktop\Capture37.PNG C:\Users\Administrator\Desktop\Capture38.PNG

Q.2 Draw two rays PQ and RS as shown in figure. Using the protractor, construct angles of 150 and 1380 with one arm PQ and RS respectively.

Soln.2 :

(i) Draw a ray PQ as given in the question.

Place the protractor on the ray PQ such that its center coincides with the point P and the diameter of the protractor coincides with PQ.

Mark a point B against the mark of 15° on the protractor.

Remove the protractor and draw PB. \( \angle QPB \) is the required angle of 15°.

(ii) Draw a ray RS as given in the question.

Place the protractor on ray RS such that its centre coincides with the point R and diameter of the protractor coincides with RS.

Mark a point T against the mark of 1380 on the protractor.

Remove the protractor and draw RJ.

\( \angle SRT \)IIs the required angle of 1380.