RD Sharma Solutions for Class 6 Maths Chapter 5: Negative Numbers and Integers Exercise 5.3

RD Sharma Solutions for Class 6 Maths Exercise 5.3 PDF

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1. Find the additive inverse of each of the following integers:

(i) 52

(ii) â€“ 176

(iii) 0

(iv) 1

Solution:

(i) The additive inverse of 52 is â€“ 52.

(ii) The additive inverse of â€“ 176 is 176.

(iii) The additive inverse of 0 is 0.

(iv) The additive inverse of 1 is â€“ 1.

2. Find the successor of each of the following integers:

(i) â€“ 42

(ii) -1

(iii) 0

(iv) â€“ 200

(v) -99

Solution:

(i) The successor of â€“ 42 is

– 42 + 1 = – 41

(ii) The successor of â€“ 1 is

-1 + 1 = 0

(iii) The successor of 0 is

0 + 1 = 1

(iv) The successor of â€“ 200 is

-200 + 1 = – 199

(v) The successor of â€“ 99 is

– 99 + 1 = – 98

3. Find the predecessor of each of the following integers:

(i) 0

(ii) 1

(iii) â€“ 1

(iv) â€“ 125

(v) 1000

Solution:

(i) The predecessor of 0 is

0 â€“ 1 = – 1

(ii) The predecessor of 1 is

1 â€“ 1 = 0

(iii) The predecessor of -1 is

-1 â€“ 1 = -2

(iv) The predecessor of â€“ 125 is

-125 â€“ 1 = – 126

(v) The predecessor of 1000 is

1000 â€“ 1 = 999

4. Which of the following statements are true?

(i) The sum of a number and its opposite is zero.

(ii) The sum of two negative integers is a positive integer.

(iii) The sum of a negative integer and a positive integer is always a negative integer.

(iv) The successor of â€“ 1 is 1.

(v) The sum of three different integers can never be zero.

Solution:

(i) True. 1 â€“ 1 = 0

(ii) False. -1 â€“ 1 = -2

(iii) False. â€“ 2 + 3 = 1

(iv) False. The successor of â€“ 1 is 0.

(v) False. 1 + 2 â€“ 3 = 0

5. Write all integers whose absolute values are less than 5.

Solution:

The integers whose absolute values are less than 5 are

-4, – 3, – 2, – 1, 0, 1, 2, 3, 4

6. Which of the following is false:

(i) |4 + 2| = |4| + |2|

(ii) |2 â€“ 4| = |2| + |4|

(iii) |4 â€“ 2| = |4| – |2|

(iv) |(-2) + (-4)| = |-2| + |-4|

Solution:

(i) True.

(ii) False.

(iii) True.

(iv) True.

7. Complete the following table:

From the above table:

(i) Write all the pairs of integers whose sum is 0.

(ii) Is (-4) + (-2) = (-2) + (-4)?

(iii) Is 0 + (-6) = -6?

Solution:

(i) The pairs of integers whose sum is 0 are

(6, -6), (4, – 4), (2, – 2), (0, 0)

(ii) Yes. By using commutativity of addition (-4) + (-2) = (-2) + (-4)

(iii) Yes. By using additive identity 0 + (-6) = -6.

8. Find an integer x such that

(i) x + 1 = 0

(ii) x + 5 = 0

(iii) â€“ 3 + x = 0

(iv) x + (-8) = 0

(v) 7 + x = 0

(vi) x + 0 = 0

Solution:

(i) x + 1 = 0

Subtracting 1 on both sides

x + 1 â€“ 1 = 0 â€“ 1

We get

x = -1

(ii) x + 5 = 0

By subtracting 5 on both sides

x + 5 â€“ 5 = 0 â€“ 5

So we get

x = -5

(iii) â€“ 3 + x = 0

By adding 3 on both sides

-3 + x + 3 = 0 + 3

So we get

x = 3

(iv) x + (-8) = 0

By adding 8 on both sides

x â€“ 8 + 8 = 0 + 8

So we get

x = 8

(v) 7 + x = 0

By subtracting 7 on both sides

7 + x â€“ 7 = 0 â€“ 7

So we get

x = – 7

(vi) x + 0 = 0

So we get

x = 0

RD Sharma Solutions for Class 6 Maths Chapter 5 – Negative Numbers and Integers Exercise 5.3

RD Sharma Solutions Class 6 Maths Chapter 5 Negative Numbers and Integers Exercise 5.3 help students understand the properties of addition of integers and ways of solving problems using them.

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• The solutions created by the faculty at BYJUâ€™S help students learn the important concepts more easily.
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