RD Sharma Solutions Class 6 Decimals Exercise 7.6

RD Sharma Solutions Class 6 Chapter 7 Exercise 7.6

RD Sharma Class 6 Solutions Chapter 7 Ex 7.6 PDF Free Download

Exercise 7.6

Question 1

Express as rupees (Rs) using decimals

i) 15 paisa

We know that 100 paisa = Rs. 1

Therefore, 1 paisa = Rs. \(\frac{1}{100}\)

15 paisa = \(\frac{15}{100}\)

= Rs 0.15

ii) 5 paisa

We know that 100 paisa = Rs. 1

Therefore, 1 paisa = Rs. \(\frac{1}{100}\)

5 paisa = \(\frac{5}{100}\)

= Rs 0.05

iii) 350

We know that 100 paisa = Rs. 1

Therefore, 1 paisa = Rs. \(\frac{1}{100}\)

35. paisa = \(\frac{350}{100}\)

= Rs 3.50

iv) 2 rupees 60 paisa

We know that 100 paisa = Rs. 1

Therefore, 1 paisa = Rs. \(\frac{1}{100}\)

2 rupees 60 paisa = 2+60100

= Rs 2.60

Question 2

Express as metres (m) using decimals

i) 15 cm

We know that 100 cm = 1m

Therefore 1 cm = \(\frac{1}{100}m\)

15cm = 15(\(\frac{1}{100}m\)) = \(\frac{15}{100}m\)

= 0.15 m

ii) 8 cm

We know that 100 cm = 1m

Therefore 1 cm = \(\frac{1}{100}m\)

8cm = 8(\(\frac{1}{100}m\)) = \(\frac{8}{100}m\)

= 0.08 m

iii) 135 cm

We know that 100 cm = 1m

Therefore 1 cm = \(\frac{1}{100}m\)

135cm = 135(\(\frac{1}{100}m\)) = \(\frac{135}{100}m\)

= 1.35m

iv) 3m 65 cm

We know that 100 cm = 1m

Therefore 1 cm = \(\frac{1}{100}m\)

3m 65cm = 3+ \(\frac{65}{100}m\)

= 3.65 m

Question 3

Express as centimetre (cm) using decimals

i) 5 mm

We know that 10 mm = 1cm

Therefore 1 mm = \(\frac{1}{10}cm\)

5 mm = \(\frac{5}{10}cm\)

= 0.5 cm

ii) 60mm

We know that 10 mm = 1cm

Therefore 1 mm = \(\frac{1}{10}cm\)

60 mm = \(\frac{60}{10}cm\)

= 6 cm

iii) 175 mm

We know that 10 mm = 1cm

Therefore 1 mm = \(\frac{1}{10}cm\)

175 mm = \(\frac{175}{10}cm\)

= 17.5 cm

iv) 4 cm 5 mm

We know that 10 mm = 1cm

Therefore 1 mm = \(\frac{1}{10}cm\)

4cm 5 mm = 4+510

= 4.5 cm

Question 4

Express as kilogram (km) using decimals

i) 5 m

We know that 1000m = 1 km

Therefore 1m = \(\frac{1}{1000}km\)

5m = \(\frac{5}{1000}km\)

= 0.005 km

ii) 55m

We know that 1000m = 1 km

Therefore 1m = \(\frac{1}{1000}km\)

55m = \(\frac{55}{1000}km\)

= 0.055 km

iii) 555m

We know that 1000m = 1 km

Therefore 1m = \(\frac{1}{1000}km\)

555m = \(\frac{555}{1000}km\)

= 0.555 km

iv) 5555m

We know that 1000m = 1 km

Therefore 1m = \(\frac{1}{1000}km\)

5m = \(\frac{5}{1000}km\)

= 5.555 km

v) 15 km 35 m

We know that 1000m = 1 km

Therefore 1m = \(\frac{1}{1000}km\)

15km35m = 15+351000

= 15.035 km

Question 5

Express each of the following without using decimals

i) 8g

We know that 1000g = 1kg

Therefore 1 g = \(\frac{1}{1000}kg\) = 0.001 kg

8g = \(\frac{8}{1000}kg\)

= 0.008 kg

ii) 150 g

We know that 1000g = 1kg

Therefore 1 g = \(\frac{1}{1000}kg\) = 0.001 kg

150g = \(\frac{150}{1000}kg\)

= 0.150 kg

iii) 2750 g

We know that 1000g = 1kg

Therefore 1 g = \(\frac{1}{1000}kg\) = 0.001 kg

2750g = \(\frac{2750}{1000}kg\)

= 2.750 kg

iv) 5 kg 750 g

We know that 1000g = 1kg

Therefore 1 g = \(\frac{1}{1000}kg\) = 0.001 kg

5 kg 750g = 5+7501000

= 5.750 kg

v) 36 kg 50 g

We know that 1000g = 1kg

Therefore 1 g = \(\frac{1}{1000}kg\) = 0.001 kg

36kg 50g = 36+501000

= 36.050 kg

Question 6

Express each of the following without using decimals

i) Rs.5.25

We know 100 paisa = 1 rupee

So , 1 paisa = \(\frac{1}{100}rupee\)

Therefore, Rs 5.25 = 5+0.25

= 5+25100 = Rs5 and 25 paisa

ii) 8.354 kg

We know that 100g = 1kg

So 1 g = \(\frac{1}{1000}kg\)

Therefore, 8.354 = 8+0.354 = 8+3541000 = 8 kg 354 g

  1. 3.5 cm

We know that 10 mm = 1cm

So, 1 mm = \(\frac{1}{10}cm\)

Therefore 3.5 = 3+0.5

= 3+510 = 3cm 5 mm

iii) 3.05 km

We know that 1000 m = 1km

Therefore 3.05 = 3+0.05

= 3+ \(\frac{5}{100}\)

= 3+ \(\frac{50}{1000}km\)

= 3km 50 m

iv) 7.54 m

We know that 100 cm = 1m

Therefore 7.54= 7+0.54

= 7+ \(\frac{54}{100}\)

= 7m 54 cm

v) 15.005 kg

We know that 1 kg =1000g

Therefore , 15.005 = 15+0.005

= 15+ \(\frac{5}{1000}\)

= 15kg 5 g

vi) 12.05 m

We know that 1m = 100 cm

Therefore 12.05 = 12+0.05

= 12+ \(\frac{5}{100}\)

= 12 m 5 cm

Practise This Question

Simplify (2+525)+(252+5)

Leave a Comment

Your email address will not be published. Required fields are marked *