Until now, we have been studying the arithmetic symbols known as numerals in the previous chapters. In this chapter, the students mainly learn about the algebraic operations conducted on various equations. RD Sharma Solutions for Class 6 are well- structured by expert faculty at BYJU’S after conducting vast research on the concepts. The primary objective is to help students improve their problem-solving abilities to boost their exam preparation. RD Sharma Solutions for Class 6 Maths Chapter 8 Introduction to Algebra Objective Type Questions PDF’s are provided here.
RD Sharma Solutions for Class 6 Maths Chapter 8: Introduction to Algebra Objective Type Questions Download PDF
Access answers to Maths RD Sharma Solutions for Class 6 Chapter 8: Introduction to Algebra Objective Type Questions
Mark the correct alternative in each of the following:
1. 5 more than twice a number x is written as
(a) 5 + x + 2
(b) 2x + 5
(c) 2x − 5
(d) 5x + 2
Solution:
The option (b) is correct answer.
5 more than twice a number x is written as 2x + 5.
2. The quotient of x by 2 is added to 5 is written as
(a)Â x/2 + 5
(b)Â 2/x+5
(c)Â (x+2)/ 5
(d)Â x/ (2+5)
Solution:
The option (a) is correct answer.
The quotient of x by 2 is added to 5 is written as x/2 + 5.
3. The quotient of x by 3 is multiplied by y is written as
(a)Â x/3y
(b)Â 3x/y
(c)Â 3y/x
(d)Â xy/3
Solution:
The option (d) is correct answer.
It can be written as
x/3 × y = xy/3
4. 9 taken away from the sum of x and y is
(a) x + y − 9
(b) 9 − (x+y)
(c)Â x+y/ 9
(d)Â 9/ x+y
Solution:
The option (a) is correct answer.
9 taken away from the sum of x and y is x + y – 9.
5. The quotient of x by y added to the product of x and y is written as
(a)Â x/y + xy
(b)Â y/x + xy
(c)Â xy+x/ y
(d)Â xy+y/ x
Solution:
The option (a) is correct answer.
The quotient of x by y added to the product of x and y is written as x/y + xy.
6. a2b3 × 2ab2 is equal to
(a) 2a3b4
(b) 2a3b5
(c) 2ab
(d)Â a3b5
Solution:
The option (b) is correct answer.
It can be written as
a2b3 × 2ab2 = 2a2 × a × b3 × b2 = 2a3b5.
7. 4a2b3 × 3ab2 × 5a3b is equal to
(a) 60a3b5
(b) 60a6b5
(c) 60a6b6
(d)Â a6b6
Solution:
The option (c) is correct answer.
It can be written as
4a2b3 × 3ab2 × 5a3b = 4 × 3 × 5 × a2 × a × a3 × b3 × b2 × b = 60a6b6
8. If 2x2y and 3xy2 denote the length and breadth of a rectangle, then its area is
(a) 6xy
(b) 6x2y2
(c) 6x3y3
(d)Â x3y3
Solution:
The option (c) is correct answer.
We know that area of a rectangle = length × breadth
By substituting the values
Area = 2x2y × 3xy2 = 6x3y3
9. In a room there are x2 rows of chairs and each two contains 2x2 chairs. The total number of chairs in the room is
(a) 2x3
(b) 2x4
(c)Â x4
(d)Â x4/2
Solution:
The option (b) is correct answer.
We know that
Total number of chairs in the room = Number of rows × Number of chairs
By substituting the values
Total number of chairs in the room = x2 × 2x2 = 2x4
10. a3 × 2a2b × 3ab5 is equal to
(a)Â a6b6
(b) 23a6b6
(c) 6a6b6
(d) None of these
Solution:
The option (c) is correct answer.
It can be written as
a3 × 2a2b × 3ab5 = 2 × 3a3 × a2 × a × b × b5 = 6a6b6
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