# RD Sharma Solutions Class 9 Linear Equation In Two Variables Exercise 13.1

## RD Sharma Solutions Class 9 Chapter 13 Ex 13.1

Q 1: Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:

(i) -2x + 3y = 12 (ii) x – y/2 – 5 = 0 (iii) 2x + 3y = 9.35  (iv) 3x = -7y (v) 2x + 3 = 0 (vi) y – 5 = 0

(vii) 4 = 3x (viii) y = x/2 ;

A 1 :

(i) We are given

– 2x + 3y = 12

– 2x  + 3y – 12 = 0

Comparing the given equation with ax+ by+ c = O

We get, a = – 2; b = 3; c = -12

(ii) We are given

x – y/2 – 5= 0

Comparing the given equation with ax + by + c = 0 ,

We get, a = 1; b = -1/2, c = -5

(iii) We are given

2x + 3y = 9.35

2x + 3y – 9.35 =0

Comparing the given equation with ax + by + c = 0

We get, a = 2 ; b = 3 ; c = -9.35

(iv) We are given

3x =-7y

3x + 7y = 0

Comparing the given equation with ax+ by + c = 0,

We get, a = 3 ; b = 7 ; c = 0

(v) We are given

2x + 3 = 0

Comparing the given equation with ax + by + c = 0,

We get, a = 2 ; b = 0 ; c = 3

(vi) We are given

Y – 5 = 0

Comparing the given equation with ax + by+ c = 0,

We get, a = 0; b = 1; c = -5

(vii) We are given

4 = 3x

3x-4=0

Comparing the given equation with ax + by + c = 0,

We get, a = 3; b = 0; c = -4

(viii) We are given

Y = x/2

Taking L.C.M => x — 2y = 0

Comparing the given equation with ax + by + c = 0 ,

We get, a = 1; b = -2; c = 0

Q 2: Write each of the following as an equation in two variables:

(i) 2x = -3            (ii) y=3  (iii) 5x = 7/ 2      (iv) y = 3/2x

A 2:

(i) We are given,

2x = —3

Now, in two variable forms the given equation will be

2x + 0y + 3=0

(ii) We are given,

y=3

Now, in two variable forms the given equation will be

0 x + y – 3 = 0

(iii) We are given,

5x = -7/2

Now, in two variable forms the given equation will be

5x + Oy +7/2 = 0

10x + Oy – 7  = 0

(iv) We are given,

$y = \frac{3}{2}x$                     (Taking L.C.M on both sides)

Now, in two variable forms the given equation will be

3x – 2y + 0 = 0

Q 3 :  The cost of ball pen is Rs 5 less than half of the cost of fountain pen. Write this statement as a linear equation in two variables.

A 3:

Let the cost of fountain pen be y and cost of ball pen be x.

According to the given equation, we have

$x = \frac{y}{2}-5$

=> 2x = y – 10

=> 2x –y + 10 = 0

Here y is the cost of one fountain pen and x is that of one ball pen.

#### Practise This Question

The probability of happening an event A is 0.5 and that of B is 0.3. If A and B are mutually exclusive events, then the probability of happening neither A nor B is