RD Sharma Solutions Class 9 Herons Formula

RD Sharma Solutions Class 9 Chapter 12

RD Sharma Solutions Class 9 Chapter 12

In earlier classes, we have learned about various plane figures such as triangles, quadrilaterals, squares, rectangles etc. We also learned the formula for finding the perimeters and areas of a square, a rectangle, and some specific triangles. In this, RD Sharma Solutions for class 9 maths chapter 12 we will learn about the famous Heron’s formula which is used for finding the area of a triangle in terms of its three sides. Suppose if a, b, c denote the lengths of the sides of a triangle ABC. The area of triangle

\(\sqrt{s(s-a)(s-b)(s-c)}\), where \(s=\frac{a+b+c}{2}\) is the semi-perimeter of triangle ABC. This formula is applicable to all types of triangles whether it is right-angled or equilateral or isosceles.

Further, we will discuss some applications of Heron’s formula. For example, if a landowner needs to find out the area of his land which is in the shape of a quadrilateral. He needs to divide the quadrilateral into triangular parts and use the heron’s formula for the area of a triangular part. Learn to apply heron’s formula easily by understanding the practice problems that are solved in RD Sharma solutions given below.


Class 9


Chapter 12


Heron’s Formula



RD Sharma Class 9 Maths Solutions – Chapter 12

Find detailed RD Sharma solutions for class 9 maths chapter 12 – heron’s formula below. Several math exercises are also given in the following table

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Practise This Question

If ΔDEFΔBCA, then the part of Δ that correspond to E is