## RD Sharma Solutions Class 9 Chapter 19

RD Sharma Solutions Class 9 Chapter 19 consists of many topics such as cylinder which is a 3D geometrical structure having 2 circular base and 2 parallel faces. The total surface area of a cylinder is equal to the sum of areas and the radius is the distance between the centers of the base to the edge of the cylinder. The bases are perpendicular to the faces of the cylinder.

The area is the total space occupied by two dimensional flat surfaces. It is measured in square units.

**Volume:** The amount of space, measured in cubic units, that an object or substance occupies.

Here is the formula which is applied for calculating the surface areas and volume of a circular cylinder.

Surface area of a cylinder = 2πr (r + h) and Volume of a cylinder = πr^{2}h

Where r = radius of the of the cylinder and h = height of the cylinder.

Practice problems on areas and volume of a circular cylinder through solved RD Sharma solutions to have a better understanding of the topic.

Class |
Class 9 |

Chapter |
Chapter 19 |

Name |
Surface Area and Volume of Right Circular Cylinder |

Exercise |
All |

## RD Sharma Class 9 Maths Solutions – Chapter 19

Here you will find several exercises of class 9 maths chapter 19 -Surface Area and Volume of Right Circular Cylinder. Click on the links to access the maths exercises from the table

Surface Area And Volume of a Right Circular Cylinder Exercise 19.1 |
Surface Area And Volume of a Right Circular Cylinder Exercise 19.2 |