RD Sharma Solutions for Class 6 Chapter 2: Playing with Numbers Exercise 2.7

RD Sharma Class 6 Solutions Chapter 2 Ex 2.7 PDF Free Download

RD Sharma Solutions for Class 6 Maths Exercise 2.7 PDF

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RD Sharma Solutions for Class 6 Chapter 2: Playing with Numbers Exercise 2.7 Download PDF

 

rd sharma solution class 6 maths chapter 6 ex 7
rd sharma solution class 6 maths chapter 6 ex 7
rd sharma solution class 6 maths chapter 6 ex 7
rd sharma solution class 6 maths chapter 6 ex 7

 

Access RD Sharma Solutions for Class 6 Chapter 2: Playing with Numbers Exercise 2.7

1. Determine the HCF of the following numbers by using Euclid’s algorithm (i – x):

(i) 300, 450

(ii) 399, 437

(iii) 1045, 1520

Solution:

(i) 300, 450

Taking 450 as dividend and 300 as divisor

RD Sharma Solutions Class 6 Chapter 2 Ex 2.7 Image 1

We know that the last divisor is 150

Therefore, HCF of 300, 450 is 150.

(ii) 399, 437

Taking 399 as dividend and 437 as divisor

RD Sharma Solutions Class 6 Chapter 2 Ex 2.7 Image 2

We know that the last divisor is 19

Therefore, HCF of 399, 437 is 19.

(iii) 1045, 1520

Taking 1045 as dividend and 1520 as divisor

RD Sharma Solutions Class 6 Chapter 2 Ex 2.7 Image 3

We know that the last divisor is 95

Therefore, HCF of 1045, 1520 is 95.

2. Show that the following pairs are co-prime:

(i) 59, 97

(ii) 875, 1859

(iii) 288, 1375

Solution:

(i) 59, 97

Taking 97 as dividend and 59 as divisor

RD Sharma Solutions Class 6 Chapter 2 Ex 2.7 Image 4

We know that the last divisor is 1.

Therefore, the numbers 59, 97 are co-prime.

(ii) 875, 1859

Taking 1859 as dividend and 875 as divisor

RD Sharma Solutions Class 6 Chapter 2 Ex 2.7 Image 5

We know that the last divisor is 1.

Therefore, the numbers 875, 1859 are co-prime.

(iii) 288, 1375

Taking 1375 as dividend and 288 as divisor

RD Sharma Solutions Class 6 Chapter 2 Ex 2.7 Image 6

We know that the last divisor is 1.

Therefore, the numbers 288, 1375 are co-prime.

3. What is the HCF of two consecutive numbers?

Solution:

We know that the HCF of two consecutive numbers is 1.

For example consider 4 and 5 as two consecutive numbers

Taking 5 as dividend and 4 as divisor

RD Sharma Solutions Class 6 Chapter 2 Ex 2.7 Image 7

We know that the last divisor is 1.

Therefore, HCF of 4 and 5 is 1.

4. Write true (T) or false (F) for each of the following statements:

(i) The HCF of two distinct prime numbers is 1.

(ii) The HCF of two co-prime number is 1.

(iii) The HCF of an even and an odd number is 1.

(iv) The HCF of two consecutive even numbers is 2.

(v) The HCF of two consecutive odd numbers is 2.

Solution:

(i) True.

(ii) True.

(iii) False. The HCF of even number 6 and odd number 9 is 3.

(iv) True.

(v) False. The HCF of numbers 25 and 27 is 1.


Access other exercise solutions of Class 6 Maths Chapter 2: Playing with Numbers

Exercise 2.1 Solutions 10 Questions

Exercise 2.2 Solutions 6 Questions

Exercise 2.3 Solutions 18 Questions

Exercise 2.4 Solutions 7 Questions

Exercise 2.5 Solutions 12 Questions

Exercise 2.6 Solutions 3 Questions

Exercise 2.8 Solutions 11 Questions

Exercise 2.9 Solutions 1 Questions

Exercise 2.10 Solutions 10 Questions

Exercise 2.11 Solutions 6 Questions

Objective Type Questions

RD Sharma Solutions Class 6 Maths Chapter 2 – Playing with Numbers Exercise 2.7

RD Sharma Solutions Class 6 Maths Chapter 2 Playing with Numbers Exercise 2.7 contains concepts like Euclid’s Algorithm and methods of finding HCF for larger numbers.

Key features of RD Sharma Solutions for Class 6 Maths Chapter 2: Playing with Numbers Exercise 2.7

  • RD Sharma Solutions are created based on the CBSE syllabus and guidelines for Class 6.
  • The solutions are provided for all the exercises which are covered in each chapter to help students perform well in the exam.
  • It helps students to obtain a clear idea about the concepts and self evaluate conceptual knowledge of each chapter.
  • The primary aim of providing solutions is to bridge the gap between students and education.

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