RD Sharma Solutions for Class 6 Maths Exercise 2.9 PDF
The solutions are designed by the subject-matter experts at BYJU’S based on the current CBSE guidelines. Students are provided with exercise-wise solutions to help them gain better knowledge about the concepts covered. Practising the examples and problems improves efficiency amongst students, while solving the solutions. The PDF of solutions can be downloaded for free and used while solving problems from the RD Sharma textbook. The self-study method is strengthened among students which helps them in performing better in the exam. RD Sharma Solutions for Class 6 Maths Chapter 2 Playing with Numbers Exercise 2.9 are provided here.
RD Sharma Solutions for Class 6 Maths Chapter 2: Playing with Numbers Exercise 2.9
Access answers to Maths RD Sharma Solutions for Class 6 Chapter 2: Playing with Numbers Exercise 2.9
1. Determine the LCM of the numbers given below:
(i) 48, 60
(ii) 42, 63
(iii) 18, 17
(iv) 15, 30, 90
(v) 56, 65, 85
(vi) 180, 384, 144
(vii) 108, 135, 162
(viii) 28, 36, 45, 60
Solution:
(i) 48, 60
We know that prime factorization of
48 = 2 × 2 × 2 × 2 × 3
60 = 2 × 2 × 3 × 5
Hence, the required LCM = 2 × 2 × 2 × 2 × 3 × 5 = 240
(ii) 42, 63
We know that prime factorization of
42 = 2 × 3 × 7
63 = 3 × 3 × 7
Hence, the required LCM = 2 × 3 × 3 × 7 = 126
(iii) 18, 17
We know that prime factorization of
18 = 2 × 3 × 3
17 = 17
Hence, the required LCM = 2 × 3 × 3 × 17 = 306
(iv) 15, 30, 90
We know that prime factorization of
15 = 3 × 5
30 = 2 × 3 × 5
90 = 2 × 3 × 3 × 5
Hence, the required LCM = 2 × 3 × 3 × 5 = 90
(v) 56, 65, 85
We know that prime factorization of
56 = 2 × 2 × 2 × 7
65 = 5 × 13
85 = 5 × 17
Hence, the required LCM = 2 × 2 × 2 × 5 × 7 × 13 × 17 = 61880
(vi) 180, 384, 144
We know that prime factorization of
180 = 2 × 2 × 3 × 3 × 5
384 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3
144 = 2 × 2 × 2 × 2 × 3 × 3
Hence, the required LCM = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 5 = 5760
(vii) 108, 135, 162
We know that prime factorization of
108 = 2 × 2 × 3 × 3 × 3
135 = 3 × 3 × 3 × 5
162 = 2 × 3 × 3 × 3 × 3
Hence, the required LCM = 2 × 2 × 3 × 3 × 3 × 3 × 5 = 1620
(viii) 28, 36, 45, 60
We know that prime factorization of
28 = 2 × 2 × 7
36 = 2 × 2 × 3 × 3
45 = 3 × 3 × 5
60 = 2 × 2 × 3 × 5
Hence, the required LCM = 2 × 2 × 3 × 3 × 5 × 7 = 1260
RD Sharma Solutions for Class 6 Maths Chapter 2 – Playing with Numbers Exercise 2.9
RD Sharma Solutions Class 6 Maths Chapter 2 Playing with Numbers Exercise 2.9 help students to understand the methods used in finding the LCM by the prime factorization and common division method.
Key Features of RD Sharma Solutions for Class 6 Maths Chapter 2: Playing with Numbers Exercise 2.9
- The solutions mainly help students understand the variety of problems that would appear in the exams.
- The examples before each exercise improves accuracy and efficiency in solving exercise-wise problems.
- RD Sharma Solutions created by subject experts help students understand the concepts in an easier way.
- Time management and self study methods are improved which are important from the exam point of view.
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