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Question

0.05F charge is passed through a lead storage battery. In the anodic reaction, what is the amount of PbSO4 precipitated (Molar mass of PbSO4 is 303g/mol)?


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Solution

Step 1: Given data:

Amount of charge passed through a lead storage battery is 0.05F

Step 2: Find the reaction that takes place at the anode:

Pb+SO4-2PbSO4+2e-Atanodeoxidationtakesplace

Step 3: Find the number of moles of PbSO4when 0.05F charge is passed:

For 1e- the charge will be 1F

But it is given that the charge is 0.05F

NumberofmolesofPbSO4formed=0.052mol

Step 4: Find the mass of PbSO4 formed:

MassofPbSO4formed=NumberofmolesofPbSO4×MolecularweightofPbSO4MassofPbSO4formed=0.052mol×303gmol-1MassofPbSO4formed=7.57g

Hence, the amount of PbSO4 precipitated is WPbSO4=7.57g


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