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Question

1sin10°-3cos10°=


A

1

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B

0

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C

2

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D

4

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Solution

The correct option is D

4


Explanation for the correct option:

Simplify using standard trigonometric identities

Let S=1sin10o3cos10o

Multiply and divide by 2:

S=212sin10o32cos10o

S=2sin30osin10ocos30ocos10o sin30°=12,cos30°=32

S=2sin30ocos10ocos30osin10osin10ocos10o

S=2sin20osin10ocos10o sinAcosB-cosAsinB=sin(A-B)

S=2×2sin10ocos10osin10ocos10o sin2θ=2sinθcosθ

S=4

Hence, Option ‘D’ is Correct.


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