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Question

12 boys and 2 girls are to be seated in a row such that there are at least 3 boys between the 2 girls. The number of ways this can be done is m×12! where m=?


A

2×C612

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B

20

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C

P211

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D

C211

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Solution

The correct option is C

P211


Explanation for the correct option:

Find the value of m:

Given that 12 boys and 2 girls are to be seated

So, arrangement of two girls sits together =2x13

=26

arrangement of one boy sits between two girls =2x12

=24

arrangement of two boys sits between two girls =2x11

=22

Total seating arrangement =14!

Thus, Required arrangement =14!(26+24+22)12!

=P211×12!

m=P211

Hence, Option ‘C’ is Correct.


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