Question

A Carnot engine operates between two reservoirs of temperature $900K$ and $300K$. The engine performs $1200J$ of work per cycle. The heat energy in$\left(J\right)$ delivered by the engine to the low-temperature reservoir, in a cycle, is

Answer 1

Step 1. Given data

Temperature, $T_1$$=900K$

Temperature, $T_2=300K$

Work done,$W=1200J$

Step 2. Finding the Efficiency, $\eta$

By using the formula for Efficiency

$\eta =1-\frac{T_2}{T_1}$

$\eta =1-\frac{300}{900}$

$\eta =\frac{2}{3}$

Step 3. Finding the heat delivered, $Q_H$

By using the formula,$\eta =\frac{W}{Q_H}$

$\frac{2}{3}=\frac{1200}{Q_H}$

$Q_H=600J$

Therefore, the heat delivered to the engine is $600J$