Question

A conducting rod of length $l$ is moving in a transverse magnetic field of strength $B$ with velocity $v$. The resistance of the rod is $R$. The current in the rod is

• A. $\frac{Blv}{R}$
• B. $\frac{B^2{l}^2{v}^2}{R}$
• C. $Zero$
• D. $Blv$

Answer 1

The correct option is A

$\frac{Blv}{R}$

Step 1. Given data:

Magnetic field strength, $B$

Length of conducting rod, $l$

Velocity, $v$

Step 2. Finding the current in the rod:

Option (A): $\frac{Blv}{R}$

The motional emf, $E$ induced in the conducting rod is given by:

$E=Blv$

The current in the rod is:

$$\begin{gathered} I=\frac{E}{R} \\ I=\frac{Blv}{R} \end{gathered}$$ $\left[E=Blv\right]$

Hence, option (A) is correct.