A lift of mass $1000 k g$ is moving with an acceleration of $1 m / s^{2}$ in an upward direction. Tension developed in the string, which is connected to the lift is $(g = 9.8 m / s^{2})$

$10, 000 N$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$10, 800 N$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$11, 000 N$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$9, 800 N$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$10, 800 N$

Step 1: Given data
Mass of the lift, $m = 1000 k g$
Acceleration of the lift in the upward direction, $a = 1 m / s^{2}$
Step 2: Find the tension in the string, $T$
Tension in the string, $T = m g + m a$
$= 1000 x 9.8 + 1000 x 1 [A s, g = 9.8 m / s^{2}] = 10800 N$
Hence, option (B) is correct.

Suggest Corrections

Similar questions

Q. A lift of mass

1000 K g

which is moving with acceleration of

1 m / s^{- 2}

in upward direction, then the tension developed in string which is connected to lift is : -

A lift of mass 1000kg , which is moving with an acceleration of 1 m/s² in upward direction has tension developed in its string equal to:

Q. A person of mass

60 k g

is inside a lift of mass

940 k g

and he presses the button on the control panel. The lift starts moving upwards with an acceleration of

1 {m / s}^{2}

. If

g = 10 {m / s}^{2}

, the tension in the supporting cable is

A boy of mass 40 kg is standing in a lift,
which is moving downwards with an acceleration 9.8 $m / s^{2}$ . The apparent weight of
the boy is (Take $g = 9.8 m / s^{2}$ )

Q. A person of mass

60 k g

inside a lift of mass

940 k g

presses the button on control panel. The lift starts moving upwards with an acceleration of 1

m / s^{2}

. If

g = 10 m / s^{2}

, the tension in the supporting cable is

Join BYJU'S Learning Program

A lift of mass 1000kg is moving with an acceleration of 1m/s2 in an upward direction. Tension developed in the string, which is connected to the lift is (g=9.8m/s2)

The correct option is B 10,800NStep 1: Given dataMass of the lift, m=1000kgAcceleration of the lift in the upward direction, a=1m/s2Step 2: Find the tension in the string, TTension in the string, T=mg+ma =1000x9.8+1000x1As,g=9.8m/s2=10800NHence, option (B) is correct.

A lift of mass $1000 k g$ is moving with an acceleration of $1 m / s^{2}$ in an upward direction. Tension developed in the string, which is connected to the lift is $(g = 9.8 m / s^{2})$