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Question

A mixture of one mole each of H2, He and O2each are enclosed in a cylinder of volume V at temperature T. If the partial pressure of H2 is 2atm, the total pressure of the gases in the cylinder is:


A

6atm

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B

14atm

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C

38atm

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D

22atm

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Solution

The correct option is A

6atm


Explanation for correct option:

(A) 6atm

  1. The total pressure of the gases in the cylinder can be calculated by using Dalton's law of partial pressure.
  2. According to Dalton's law of partial pressure pi=xi×Pt Where, pi is pressure of gas i in the mixture of gases, xi is mole fraction of gas i and Pt is the total pressure of gases.
  3. We know that the partial pressure of H2 gas in the mixture is 2atm and number of moles of each gas is 1mole.
  4. Now, reforming the equation to use it we get: Pt=nH2+nHe+no2nH2×pi
  5. Placing the known values in the equation: Pt=31×2Pt=6
  6. So, here we can see that total pressure of the gases is 6atm.

Explanation for incorrect options:

(B) 14atm

  1. According to Dalton's law of partial pressure the total pressure of gases is calculated above.
  2. So option B is incorrect.

(C) 38atm

  1. According to Dalton's law of partial pressure the total pressure of gases is calculated above.
  2. So option C is incorrect.

(D) 22atm

  1. According to Dalton's law of partial pressure the total pressure of gases is calculated above.
  2. So option D is incorrect.

Hence option A is correct, the total pressure of the gases in the cylinder is 6atm.


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