A particle of mass $2 m g$ moves with constant speed and is found to pass two points $5.0 m$ apart in a time interval of $5 m s$ . Find the kinetic energy of the particle

$1 J$

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$2 J$

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$3 J$

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$4 J$

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Solution

The correct option is A
$1 J$

Step 1: Given data.
Mass of the particle, $2 m g = 2 \times 10^{- 3} g$
Distance, $d = 5 m$
Time, $t = 5 s$
Step 2: Finding the kinetic energy of the particle.
Formula used:
Kinetic energy, $K E = \frac{1}{2} m v^{2}$
We know that,
Velocity, $v = \frac{d}{t}$
$\Rightarrow$ $v = \frac{5}{5 \times 10^{- 3}}$
$\Rightarrow$ $v = 10^{3} \frac{m}{s}$
Now,
$K E = \frac{1}{2} m v^{2}$
$\Rightarrow$ $K E = \frac{1}{2} \times 2 \times 10^{- 3} \times {(10^{3})}^{2}$
$\Rightarrow$ $K E = 1 J$
Hence, option A is correct.

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A particle of mass 2mg moves with constant speed and is found to pass two points 5.0m apart in a time interval of 5ms. Find the kinetic energy of the particle

A particle of mass $2 m g$ moves with constant speed and is found to pass two points $5.0 m$ apart in a time interval of $5 m s$ . Find the kinetic energy of the particle