wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A potentiometer wire PQ of 1m length is connected to a standard cell E1. Another cell E2 of emf 1.02V is connected with a resistance r and switch S (as shown in figure). With switch S open, the null position is obtained at a distance of 49cm from Q. The potential gradient in the potentiometer wire is:

JEE Main 2020 Solutions Physics Shift2-2nd Sept

  1. 0.03V/cm

  2. 0.02V/cm

  3. 0.04V/cm

  4. 0.01V/cm

Open in App
Solution

The correct option is B

0.02V/cm


Step 1: Given data

PQ=1mQJ=49cmPJ=51cmE2=1.02V

JEE Main 2020 Shift2-2nd Sept Solutions Physics

Step 2: Find potential gradient

Potential gradient is given by,

Potentialgradient=Potentialdroplength

=1.0251=0.02v/cm

Hence, option (B) is correct.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
emf and emf Devices
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon