A spring of force constant 800Nm-1 has an extension of 5cm. The work done in extending it from 5cm to 15cm is
16J
8J
32J
24J
Step 1: Given data
Force constant k=800Nm-1
Step 2: Find work done
The work done is given by,
W=(1/2)k(x22–x12)W=(1/2)x800x(0.152–0.052)W=(1/2)x800x(0.0225–0.0025)W=400x0.02W=8N/mW=8J
Hence, option B is correct.