A steel wire fixed at both ends has a fundamental frequency of $200 H z$ . A person can hear sound of maximum frequency $14 k H z$ . What is the highest harmonic that can be played on this string which is audible to the person?

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Solution

Step 1: Given data.
Fundamental frequency, $f_{0} = 200 H z$
Highest harmonic frequency, $f' = 14 k H z = 14000 H z$
Step 2: Finding the highest harmonic audible to the person.
We know that,
highest harmonic frequency,
$f' = n \times f_{0}$
$\Rightarrow$ $n = \frac{14000}{200}$
$\Rightarrow$ $n = 70$
Hence, the highest harmonic audible to the person is $70 t h$ harmonic.

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A steel wire fixed at both ends has a fundamental frequency of 200Hz. A person can hear sound of maximum frequency 14kHz. What is the highest harmonic that can be played on this string which is audible to the person?

Step 1: Given data.Fundamental frequency, f0=200HzHighest harmonic frequency, f'=14kHz=14000HzStep 2: Finding the highest harmonic audible to the person.We know that,highest harmonic frequency, f'=n×f0⇒n=14000200⇒n=70Hence, the highest harmonic audible to the person is 70thharmonic.

A steel wire fixed at both ends has a fundamental frequency of $200 H z$ . A person can hear sound of maximum frequency $14 k H z$ . What is the highest harmonic that can be played on this string which is audible to the person?