Question

A wave pulse passing on a string with a speed of $40cm{s}^{-1}$in the negative $X-direction$ has its maximum at $x=0att=0$ . Where will this maximum be located at $t=5s$?

Answer 1

Step 1. Given Data,

$$\begin{gathered} Velocity,v=40cm{s}^{-1} \\ Time,t=5s \end{gathered}$$

Given that the wave pulse passes on a string in the negative direction, which has its maximum at $x=0att=0$.

Step 2. Location of maximum at $t=5s$,

We know that,

$$\begin{gathered} Velocity=\frac{Dis\tan ce}{Time} \\ v=\frac{x}{t} \\ \Rightarrow x=vt \\ \Rightarrow x=40cm{s}^{-1}\times 5s \\ \Rightarrow x=200cm \end{gathered}$$

Hence, The location of the maximum is $x=200cm$.