Question

Among statements I - IV, the correct ones are:

I. Decomposition of hydrogen peroxide gives dioxygen

II. Like hydrogen peroxide, compounds, such as KClO₃, Pb(NO₃)₂ and NaNO₃ when heated liberate dioxygen.

III. $2-\mathrm{Ethylanthraquinone}$ is useful for the industrial preparation of hydrogen peroxide.

IV. Hydrogen peroxide is used for the manufacture of sodium perborate

• A. I, II, III and IV
• B. I, II and III only
• C. I, III and IV only
• D. I and III only

Answer 1

The correct option is A

I, II, III and IV

Explanation for the correct option:

(A) I, II, III and IV

• Statement I: Decomposition of Hydrogen peroxide:
• ${\mathrm{H}}_2{\mathrm{O}}_2\to 2{\mathrm{H}}_2\mathrm{O}+{\mathrm{O}}_2$ So, from the reaction it can be observed that we can obtain dioxygen on the decomposition of Hydrogen peroxide.
• Statement II: Heating of compounds ${\mathrm{KClO}}_3$ and $\mathrm{Pb}{\left({\mathrm{NO}}_3\right)}_2$:
• ${\mathrm{KClO}}_3\underset{{\mathrm{MnO}}_2}{\overset{∆}{\to }}\mathrm{KCl}+\frac{3}{2}{\mathrm{O}}_2$
• $\mathrm{Pb}{\left({\mathrm{NO}}_3\right)}_2\stackrel{∆}{\to }\mathrm{PbO}+2{\mathrm{NO}}_2+\frac{1}{2}{\mathrm{O}}_2$ Here, it can be observed from the reaction that compounds like ${\mathrm{H}}_2{\mathrm{O}}_2$ also form dioxygen on heating.
• Statement III: Industrial preparation of Hydrogen peroxide $\left({\mathrm{H}}_2{\mathrm{O}}_2\right)$:
• $2-\mathrm{ethylanthraquinoline}\underset{{\mathrm{H}}_2/\mathrm{Pd}}{\overset{{\mathrm{O}}_2\left(\mathrm{air}\right)}{\rightleftharpoons }}2-\mathrm{ethylanthraquinoline}+{\mathrm{H}}_2{\mathrm{O}}_2$. From the reaction, it can be seen that $2-\mathrm{Ethylanthraquinone}$ is useful in the industrial preparation of ${\mathrm{H}}_2{\mathrm{O}}_2$.
• Statement IV: Manufacturing of sodium perborate:

1. $$\begin{gathered} 2{\mathrm{H}}_3{\mathrm{BO}}_3+2\mathrm{NaOH}+2{\mathrm{H}}_2{\mathrm{O}}_2\to {\mathrm{Na}}_2\left[{\mathrm{B}}_2\left({\mathrm{O}}_2\right){\left(\mathrm{OH}\right)}_4\right]+4{\mathrm{H}}_2\mathrm{O} \\ \mathrm{Sodium}\mathrm{perborate} \end{gathered}$$ It can be seen from the reaction that Sodium perborate can be synthesized by using Hydrogen peroxide.