An alternating voltage is represented as $E = 20 \sin 300 t$ . The average value of voltage over one cycle will be

$z e r o$

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$10 v o l t$

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$20 \sqrt{2} v o l t$

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$(20 / \sqrt{2}) v o l t$

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Solution

The correct option is A
$z e r o$

Correct option is A: zero
Explanation for the correct option:
The average value of any AC voltage over a cycle is equal to zero as it will have equal values for both positive and negative cycles.
Average values of sine function over one cycle is always zero.
This will cancel out each other and resultant is zero.
Hence, option A is correct.

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v o l t

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