Question

Consider the following chemical reaction:

$\mathrm{CH}\equiv \mathrm{CH}\underset{2.\mathrm{CO},\mathrm{HCl},{\mathrm{AlCl}}_3}{\overset{1.\mathrm{Red}\mathrm{hot}\mathrm{Fe}\mathrm{tube},873\mathrm{K}}{\to }}\mathrm{Product}$

The ${\mathrm{sp}}^2$hybridized carbon atom(s) present in the product is ___________.

Answer 1

1. The given reaction is represented as follows:
2. 
3. As it can be observed from the above reaction, the final product formed is benzaldehyde.
4. ${\mathrm{sp}}^2$hybridization is the mixing of one $\mathrm{s}$ and two $\mathrm{p}$ orbitals.
5. Now, ${\mathrm{sp}}^2$ hybridization is shown by all the compounds having $\mathrm{C}-\mathrm{C}$ double bonds.
6. In benzaldehyde, all the $\mathrm{C}$- atoms have double bonds, hence all the $\mathrm{C}$- atoms are ${\mathrm{sp}}^2$ hybridized.