Question

Consider the following reaction and statements ${\left[\mathrm{Co}{\left({\mathrm{NH}}_3\right)}_4{\mathrm{Br}}_2\right]}^{+}+B{r}^{-}\underset{}{\overset{}{\to }}\left[Co{\left(N{H}_3\right)}_{3}B{r}_3\right]+N{H}_3$

(I) Two isomers are produced if the reactant complex ion is a cis-isomer.

(II) Two isomers are produced if the reactant complex ion is a trans-isomer.

(III) Only one isomer is produced if the reactant complex ion is a trans-isomer.

(IV) Only one isomer is produced if the reactant complex ion is a cis-isomer.

The correct statements are:

• A. (I) and (III)
• B. (III) and (IV)
• C. (II) and (IV)
• D. (I) and (II)

Answer 1

The correct option is A

(I) and (III)

The explanation for the correct option:

(A): For Cis-isomer:

The above reaction diagram shows that the cis isomer produces two isomers.

For trans-isomer:

The above reaction diagram shows that trans isomer produces only one isomer.

Hence, cis-isomer gives two isomers while trans-isomer gives only one isomer.

The explanation for the incorrect option:

(B) In the case of trans-isomer, only one isomer is produced. However, one isomer is not obtained in the case of cis-isomer. Hence, option B is incorrect.

(C) In the case of cis-isomer, one isomer is not obtained and in the case of trans-isomer, two isomers are not obtained. Hence, option C is incorrect.

(D) In the case of cis-isomer, two isomers are obtained. However, two isomers are not obtained in the case of trans-isomer. Hence, option B is incorrect.

Hence, option A is correct.