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Question

Consider the system of equationsx+y+z=1,2x+3y+2z=1,2x+3y+(a2-1)z=a+1 then


A

System has a unique solution for|a|=3

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B

System is inconsistence for|a|=3

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C

System is inconsistence fora=4

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D

System is inconsistence fora=3

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Solution

The correct option is B

System is inconsistence for|a|=3


Step 1: Use Cramer's rule

We have given a system of equations

x+y+z=1,2x+3y+2z=1,2x+3y+(a2-1)z=a+1

by Cramer's rule,

D=11123223a2-1D=1[3(a2-1)-6]-1[2(a2-1)-4]+1[6-6]D=(a2-1)-6+4+0D=a2-3

Step 2: Checking the system of equations consistence or inconsistence.

IfD=0, System of equations has inconsistence solution.

IfD0, System of equations has a unique solution.

a2-3=0a2=3a=±3|a|=3

Hence, option(B) is correct.


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