Distance between the parallel lines 3x+4y+7=0and 3x+4y-5=0 is
25
125
512
35
Finding distance between parallel line :
Given: 3x+4y+7=0…(i)3x+4y–5=0…(ii)
Distance between two parallel lines,=7+532+42d=c1-c2a12+b12
=125
Hence, Option (B) is correct.
Find the ratio in which the line 3x+4y+2=0 divides the distance between the lines 3x+4y+5=0 and 3x+4y−5=0.
The ratio in which the line 3x+4y+2=0 divides the distance between the lines 3x+4y=0 and 3x+4y−5=0 is